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Talja [164]
3 years ago
7

What mass of hydrogen gas can be produced by 6.0 mol of aluminum with hydrochloric acid?

Chemistry
1 answer:
Agata [3.3K]3 years ago
3 0
2Al + 6HCl = 2AlCl₃ + 3H₂

m(H₂)=3M(H₂)n(Al)/2

m(H₂)=3*2.0g/mol*6.0mol/2=18.0 g
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Students are measuring the length of time it takes for soda to go flat at three different temperatures. Which type of graph shou
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A photon has 8.0 × 10–15 J of energy. Planck’s constant is 6.63 × 10–34 J•s. What is the frequency of the photon
german
The formula is:
frequency * h (Planck's constant) = Energy
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5 0
3 years ago
Read 2 more answers
How many different substituents are required on a carbon atom for it to be chiral?
zheka24 [161]

Four different substituents are required on a carbon atom for it to be chiral.

<h3>What is Chiral Carbons ?</h3>

The carbon atom which is attached with four different types of group of atoms or atoms is called Chiral carbon. Chiral molecules are non superimposable on their mirror images. Chiral carbon is also called asymmetric carbon.

Example:

Br - \underset{H} {\underset{|} {\overset{CH_3}  {\overset{|}{C}}}} - Cl

In the above example we can see that carbon atom has 4 different group attached with it that is Br, Cl, H, CH₃.

Thus from the above conclusion we can say that Four different substituents are required on a carbon atom for it to be chiral.

Learn more about the Chiral carbon here: brainly.com/question/1195366

#SPJ4

6 0
2 years ago
At a certain temperature, 0.760 mol SO3 is placed in a 1.50 L container. 2SO3(g) = 2SO2(g) + O2(g)At equilibrium, 0.130 mol O2 i
olganol [36]

Answer:

K_c=0.0867

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.760}{1.50\ L}

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

\begin{matrix} & 2SO_3_{(g)} & \rightleftharpoons & 2SO_2_{(g)} & + & O_2_{(g)}\\At\ time, t = 0 & 0.5067 &&0&&0 \\ At\ time, t=t_{eq} & -2x &&2x&&x \\----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:- &0.5067-2x&&2x&&x\end{matrix}

Given:    

Equilibrium concentration of  O₂ = 0.130 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.130}{1.50\ L}

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_2]^2[O_2]}{[SO_3]^2}  

K_c=\frac{(0.3334)^2\times 0.0867}{(0.3334)^2}

K_c=0.0867

5 0
3 years ago
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