Answer:
Se requerirán 14.57 gramos de MgSO₄·7H₂O, que se disolverían en 105.43 gramos de agua.
Explanation:
Si tenemos 120 gramos de una solución al 10% de sulfato de magnesio en peso, habrán en la solución (120*10/100) 12 gramos de sulfato de magnesio (MgSO₄).
Sin embargo, el reactivo que está disponible es heptahidratado (MgSO₄·7H₂O), por lo que hay que calcular <em>cuántos gramos de sulfato de magnesio heptahidratado contendrán 12 gramos de MgSO₄</em>.
<u>Calculamos las moles de 12 gramos de MgSO₄</u>, usando su masa molecular:
- 12 g MgSO₄ ÷ 120.305 g/mol = 0.0997 mol MgSO₄.
<u>Después calculamos la masa de MgSO₄·7H₂O que contendrá 0.0997 mol MgSO₄</u>, usando la masa molecular de MgSO₄·7H₂O:
- 0.0997 mol * 246.305 g/mol = 14.57 g MgSO₄·7H₂O
Para saber la cantidad de agua en la que se disolverá el reactivo, restamos la masa de soluto de la masa total de la solución:
- 120 g - 14.57 g = 105.43 g
If the liquid is at or above its flash point, the flame spread rate is fast, and the entire pool is engulfed within seconds. ... As the liquid temperature decreases, flame radiation must both heat the liquid to the flash point temperature and supply the heat of vaporization.
Answer:
it's just like doing a test grade on children if you give them different tests they might not come up with the same results, the molecules need to be the same or else the experiment will be even.
Explanation:
whenever water is hot the molecules will bounce really fast in the bottle, whenever water is cold he will go really slow in the bottle
Answer:
60.55%
Explanation:
nO3=155/48
nO2 used: 3/2nO3=4.84375
percent yield: 4.84375/8=60.55%
Answer:
When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level. The energy of the photon is the exact energy that is lost by the electron moving to its lower energy level.
Explanation:
