Answer:
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?
(16 over 9) = 16!/(9!*7!) = 11440
2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?
52*51*50 = 132600
3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?
52^3 = 140608
4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?
(5 over 3) = 5!/(3! * 2!) = 10
5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?
10/40^3 = 1/6400
Very very simple so back in my day when people have been wondering on this app waddling and waddling they think they can do it when they go it is the easiest of the easiest way for me a duck rubber kind intact it is 15
It's simple, just subtract 3 from 6 because the have the same terms and variables then keep your answer as it should be. you should get 4b³c²+3b²c³
Theorem: If two chords intersect within a circle, then the product of the lengths of the segments (parts) of one chord is equal to the product of the lengths of the segments of the other chord.
In your case this theorem sounds as
Solve this equation:
Answer: correct choice is C.
Answer:
<h2>
-24 + 22i</h2>
Step-by-step explanation:
Use the FOIL method of multiplication of binomials:
(-4+2i)(7-2i) = -28 + 14i + 8i - (-4)i²
Note that i² = -1. Thus, - (-4)i² = +4, and we then have:
-28 + 22i + 4, or
-24 + 22i
