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2 years ago

CAN SOMEONE PLZ HELP ME

Mathematics

2 answers:

cestrela7 [59]2 years ago

7 0

Answer:

the first one

4*10^12

Step-by-step explanation:

Viefleur [7K]2 years ago

5 0

Answer:

4000000000

Step-by-step explanation:

(600000000) / (0.00015)

4000000000

4*10^12

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F(x) =10x 5 and g(x) =3x 6 then what is ( f-g)

padilas [110]

(10x 5 - 3x 6)
(50x - 18x)
(f-g) = 32x

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3 years ago

at the beginning of a chemistry experiment the volume of liquid in a container was 4 milliliters. during the experiment the volu

Mrac [35]

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Step-by-step explanation:

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2 years ago

How do you factor 5 out of 5x+40

VARVARA [1.3K]

Answer:

To factor something out you've got to divide, so you would take 5x+40 and divide it all by 5

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3 years ago

Read 2 more answers

If x is -3 and y is 2 what is x ^ 2 + y ^ 2

Pavlova-9 [17]

Answer:

ans=-2

Step-by-step explanation:

-3*2+2*2

=-6+4

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4 0

3 years ago

Find the values of k so that each remainder is three. 10. (x^2+ 5x + 7) = (x + k)

Goryan [66]

Answer:

$k=1\text{ or } k=4$

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a binomial in the form (x - a), then our remainder will be P(a).

We are dividing:

$(x^2+5x+7)\div(x+k)$

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

$(-k)^2+5(-k)+7=3$

Simplify:

$k^2-5k+7=3$

Solve for k. Subtract 3 from both sides:

$k^2-5k+4=0$

Factor:

$(k-1)(k-4)=0$

Zero Product Property:

$k-1=0\text{ or } k-4=0$

Solve:

$k=1\text{ or } k=4$

So, either of the two expressions:

$(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)$

Will yield 3 as the remainder.

5 0

3 years ago