I NEED HELP please my brain

1 answer:

6 0

What’s wrong? What happen to your brain? Brain pain? Here are some tips:

1.)Try a Cold Pack. If you have a migraine,
2.)place a cold pack on your forehead
3.)Use a Heating Pad or Hot Compress.
4.)Ease Pressure on Your Scalp or Head.
5.)Dim the Lights.
6.)Try Not to Chew.
7.)Get Some Caffeine.
8.)Practice Relaxation.
9.)Take Some Ginger.

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Cooommmon guys help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!plz

Tom [10]

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (5, -3) and (-2, 9). Substitute:

$m=\dfrac{9-(-3)}{-2-5}=\dfrac{12}{-7}=-\dfrac{12}{7}\\\\y-(-3)=-\dfrac{12}{7}(x-5)\\\\\boxed{y+3=-\dfrac{12}{7}(x-5)}$

5 0

3 years ago

Read 2 more answers

Which value for "a" completes the conditional relative frequency table by row?

irinina [24]

Answer:

a=0.1

Step-by-step explanation:

From the given frequency table, Fiction= Poetry+Prose=total

⇒0.2+0.8=1.0=total

And, Poetry+prose= total

⇒0.18+0.82=1.0= total

Thus, following the same path,we have

Non Fiction= Poetry+prose=Total

⇒a+0.9=1.0

⇒a=1.0-0.9

⇒a=0.1

Therefore, the value of a will be: 0.1

8 0

3 years ago

Read 2 more answers

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: