Yes because if they are further away it makes it hard for them to attract each other
Answer:
Please refer to the figure.
Explanation:
The crucial point here is to calculate the enclosed current. If the current I is flowing through the whole cross-sectional area of the wire, the current density is
![J = \frac{I}{\pi R^2}](https://tex.z-dn.net/?f=J%20%3D%20%5Cfrac%7BI%7D%7B%5Cpi%20R%5E2%7D)
The current density is constant for different parts of the wire. This idea is similar to that of the density of a glass of water is equal to the density of a whole bucket of water.
So,
![J = \frac{I}{\pi R^2} = \frac{I_{enc}}{\pi r^2}\\I_{enc} = \frac{Ir^2}{R^2}](https://tex.z-dn.net/?f=J%20%3D%20%5Cfrac%7BI%7D%7B%5Cpi%20R%5E2%7D%20%3D%20%5Cfrac%7BI_%7Benc%7D%7D%7B%5Cpi%20r%5E2%7D%5C%5CI_%7Benc%7D%20%3D%20%5Cfrac%7BIr%5E2%7D%7BR%5E2%7D)
This enclosed current is now to be used in Ampere’s Law.
![\mu_o I_{enc} = \int {B} \, dl](https://tex.z-dn.net/?f=%5Cmu_o%20I_%7Benc%7D%20%3D%20%5Cint%20%7BB%7D%20%5C%2C%20dl)
Here,
represents the circular path of radius r. So we can replace the integral with the circumference of the path,
.
As a result, the magnetic field is
![B = \frac{\mu_0}{2\pi}\frac{Ir}{R^2}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Cmu_0%7D%7B2%5Cpi%7D%5Cfrac%7BIr%7D%7BR%5E2%7D)
C. is correct. when you make a pizza, you see the the meat or pepperoni or cheese heating up and sometimes melted. (thats physical). on the inside the crust in heated and the toppings are cooked (chemical)
The ratio of the maximum photoelectron kinetic energy to the work function will be 3:1.
<h3 /><h3>What is the photoelectric effect?</h3>
When a medium receives electromagnetic radiation, electrostatically charged particles are emitted from or inside it.
The emission of ions from a steel plate when light falls on it is a common definition of the effect. The substance could be a solid, liquid, or gas; and the released particles could be protons or electrons.
A particular metal emits photoelectrons when exposed to light with energy three times its work function:
![\rm KE=3 \phi](https://tex.z-dn.net/?f=%5Crm%20KE%3D3%20%5Cphi)
The ratio of the maximum photoelectron kinetic energy to the work function will be;
![R=\frac{E}{\phi} \\\\ R=\frac{3 \phi}{\phi} \\\\ R= 3](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BE%7D%7B%5Cphi%7D%20%5C%5C%5C%5C%20R%3D%5Cfrac%7B3%20%5Cphi%7D%7B%5Cphi%7D%20%5C%5C%5C%5C%20R%3D%203)
Hence, the ratio of the maximum photoelectron kinetic energy to the work function will be 3:1.
To learn more about the photoelectric effect refer to the link;
brainly.com/question/9260704
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