Answer:
6.53 m/s²
Explanation:
Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.
Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:
T = m₁a (1)
m₂g - T = m₂a (2)
substituting T = m₁a in equation 2:
m₂g - m₁a = m₂a
m₂a + m₁a = m₂g
a(m₁ + m₂) = m₂g
a = m₂g / (m₁ + m₂)
a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²
Both objects have an acceleration of 6.53 m/s²
Answer:
%
Explanation:
We have given cooler temperature that is 
= 6°C =273+6=279 K
And the warm temperature of water that is 
The maximum possible efficiency is given by 
So maximum efficiency 
%
It defines that if two thermodynamic systems are each in equilibrium with a third system, then they are in equilibrium with each other.
Answer:
a' =4.15 m/s²
Explanation:
Given that
m= 3.2 kg
F₁ = 1.9 i −1.9 j N
F₂=3.8 i −10.1 j N
From second law of Newton's
F(net) = m a
F₁ + F₂ = m x a
1.9 i −1.9 j + 3.8 i −10.1 j = 3.2 a
a = 1.78 i - 3.75 j m/s²
The resultant acceleration a'
a' =4.15 m/s²
