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Paul [167]
3 years ago
5

2. A car going 35 km/hr takes 23.0 s to come to a stop at the red light. What is it's

Physics
1 answer:
viktelen [127]3 years ago
6 0

Answer:-0. 42m/s^2

Explanation:

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200 what factors do Pressure depend?<br>1 What is a<br>thematical expression do you u​
Varvara68 [4.7K]

Answer:

pressure of solid depends on:

1/magnitude of the force

2/contact area

pressure in solid depends on:

1/depth inside the fluid.

2/density of the fluid.

3/Acceleration due to gravity.

Explanation:

1/magnitude of the force:the pressure is directly proportional to the magnitude of the force(thrust). The larger the force, the higher is the magnitude of pressure on the surface.

2/Contact area: the pressure is inversely proportional to the surface area of contact. The larger the contact area, lower is the magnitude of the pressure.

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2 years ago
What is the purpose of an experiment design?
Eddi Din [679]
An experimental design is used to assign variables for testing. In contrast to a control design where nothing is changed, the experimental design allows you to test various new inputs to see how they would vary from the original results.
5 0
3 years ago
A -kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the tra
Tatiana [17]

Answer:

The centripetal acceleration of the car is 8\ m/s^2.

Explanation:

Let the mass of the car, m=10^3\ kg

Diameter of the circular path, d = 100 m

Speed of car, v = 20 m/s

Radius, r = 50 m

When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(20\ m/s)^2}{50\ m}

a=8\ m/s^2

So, the centripetal acceleration of the car is 8\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
What is a quantum field?
liubo4ka [24]
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8 0
3 years ago
Read 2 more answers
In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
Alina [70]

Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = \frac{K*q}{d^2}*d = \frac{K*q}{d}

d = \frac{K*q}{V}

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063

d = 914.41 X 10³ m

Therefore, the distance between the two spheres is 914.41 X 10³ m

3 0
3 years ago
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