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olasank [31]
3 years ago
15

What’s the answer ???

Physics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

i cant even see it

Explanation:

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A typical oil control ring consists of _______ separate part(s).
azamat
<span>A. three</span><span>

Oil spill can be very harmful to marine life because  the chemical make up of oils can be poisonous to marine life. The oil can also affect the natural body temperature of marine animals especially to the small fish. Sea otters and sea birds are the most commonly affected by oil spills and those other marine animals that can be found in the shoreline. Heavy oils like the bunker oils used to fuel ships are the most harmful oil because when this oil stick to birds feathers, they may have an inability to warm themselves that could lead them to die.</span>
5 0
3 years ago
Read 2 more answers
A robot is on the surface of Mars. The angle of depression from a camera in the robot to a rock on the surface of Mars is 13.69
ra1l [238]

Answer:

The distance between the camera and the rock is 836.6 cm

Explanation:

A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:

cos α = adjacent/hypotenuse

cos(76.31) = 198.0/h

h = 198.0/cos(76.31)

h = 836.6 cm

3 0
4 years ago
A scientist is studying the effect on human health of bacteria that live in the human intestine. In her study, she found that th
irga5000 [103]
70 is the correct awnser
5 0
3 years ago
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1. The property of a material to absorb liquid like water is called
frez [133]

Answer:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

Explanation:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

3 0
3 years ago
A concert loudspeaker suspended high off the ground emits 31 W of sound power. A small microphone with a 1.0 cm^2 area is 42 m f
Aleonysh [2.5K]

Answer:

intensity of sound at level of microphone is 0.00139 W / m 2

sound intensity level at position of micro phone is 91.456 dB

EXPLANATION:

Given data:

power of sound   P = 31 W

distance betwen microphone & speaker is   42 m

a) intensity of sound at microphone is calculated as

                   I = \frac{P}{A}

                   = \frac{34}{4 \pi ( 44m )^ 2}

                   =  0.00139 W / m 2        

b) sound intensity level at position of micro phone is

                \beta = 10 log \frac{I}{I_o}

    where I_o id reference sound intensity and taken as

                = 1 * 10^{-12} W / m 2  

               \beta = 10 log\frac{0.00139}{10^[-12}}

                     = 91.456 dB

7 0
3 years ago
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