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3 years ago

When a wave is acted upon by an external damping force, what happens to the energy of the wave

Physics

2 answers:

Rasek [7]3 years ago

8 0

The energy of the wave decreases gradually

bazaltina [42]3 years ago

3 0

Answer:

Explanation:

The energy of the wave its determined by the mass of the fuid of the wave and the speed. The amount of motion equation P= m.v

So according to the impulse and amount of motion theorem (ΔP= mvₙ- mv₀).

If the wave is acted upon by an external dumping force, the wave its going to decrease his energy because the reduction of the speed and the mass.

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Instead of moving back and forth, a conical pendulum moves in a circle at constant speed as its string traces out a cone (see fi

tigry1 [53]

Answer:

The radial acceleration is $a_c = 0.9574 m/s^2$

The horizontal Tension is $T_x = 0.3294 i \ N$

The vertical Tension is $T_y =3.3712 j \ N$

Explanation:

The diagram illustrating this is shown on the first uploaded

From the question we are told that

The length of the string is $L = 10.7 \ cm = 0.107 \ m$

The mass of the bob is $m = 0.344 \ kg$

The angle made by the string is $\theta = 5.58^o$

The centripetal force acting on the bob is mathematically represented as

$F = \frac{mv^2}{r}$

Now From the diagram we see that this force is equivalent to

$F = Tsin \theta$ where T is the tension on the rope and v is the linear velocity

$Tsin \theta = \frac{mv^2}{r}$

Now the downward normal force acting on the bob is mathematically represented as

$Tcos \theta = mg$

$\frac{Tsin \ttheta }{Tcos \theta } = \frac{\frac{mv^2}{r} }{mg}$

=> $tan \theta = \frac{v^2}{rg}$

=> $g tan \theta = \frac{v^2}{r}$

The centripetal acceleration which the same as the radial acceleration of the bob is mathematically represented as

$a_c = \frac{v^2}{r}$

=> $a_c = gtan \theta$

substituting values

$a_c = 9.8 * tan (5.58)$

$a_c = 0.9574 m/s^2$

The horizontal component is mathematically represented as

$T_x = Tsin \theta = ma_c$

substituting value

$T_x = 0.344 * 0.9574$

$T_x = 0.3294 \ N$

The vertical component of tension is

$T_y = T \ cos \theta = mg$

substituting value

$T_ y = 0.344 * 9.8$

$T_ y = 3.2712 \ N$

The vector representation of the T in term is of the tension on the horizontal and the tension on the vertical is

$T = T_x i + T_y j$

substituting value

$T = [(0.3294) i + (3.3712)j ] \ N$

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3 years ago

An unknown substance is tested and found to have the following physical properties: brittle fair conductor of electricity dull (

nikklg [1K]

The answer is <span>metalloid </span>

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3 years ago

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A car starts from rest and travels for t1 seconds with a uniform acceleration a1. The driver then applies the brakes, causing a

mestny [16]

The answer for this question is b because it says how far it goes before he begins to take brake

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2 years ago

What is the displacement of the particle in the time interval 7 seconds to 8 seconds? A. 0 meters B. 1.5 meters C. 3 meters D. 7

Dmitrij [34]

Answer: B. 1.5 meters

Explanation:

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2 years ago

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The tallest Ferris wheel in the world is located in Singapore. Standing 42 stories high and holding as many as 780 passengers, t

kakasveta [241]

Answer:

The speed of the riders on the Singapore Flyer is approximately 0.262 m/s

Explanation:

The dimensions of the tallest Ferris wheel in the world are;

The diameter of the Ferris wheel, D = 150 m

The tine it takes the Ferris wheel to make a full circle, T = 30 minutes = 30 min × 60 s/min = 1,800 seconds

The angular velocity of the Ferris wheel, ω = 2·π/T

The linear velocity of the Ferris wheel, v = r·ω = The speed of the riders

Where;

r = The radius of the Ferris wheel = D/2

D = 150 m

∴ r = 150 m/2 = 75 m

∴ v = r·2·π/T

∴ v = 75 m × 2 × π/(1,800 s) ≈ 0.262 m/s

The speed of the riders on the Singapore Flyer, v ≈ 0.262 m/s

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3 years ago