Ok,
Let's check to see if he catches it before he reaches 8 m/s.
Velocity = acceleration * time, V = at,
so 8 m/s = 3.4 m/s * t, so t = 2.35 sec
in that time he moved
Distance = Initial Velocity * time + 1/2 acceleration * time * time
S = 0*2.35 + 1/2*3.4*2.35*2.35 = 9.4 meters
in 2.35 seconds, the boxcar moved
S = V*t = 4.5 * 2.35 = 10.59 meters, so he still needs to catch up
10.59 m - 9.4 m = 1.19 meters. Since he is now moving at 8 m/s and the train is moving at 4.5 m/s, his closing speed is (8 - 4.5) = 3.5 m/s
It will take him 1.19m/3.5m/s = .34 seconds more to catch up.
So answer A is 2.35 sec + .34 sec = 2.69 seconds.
For answer B we use the speed of the train since it was constant,
<span>Distance = Velocity * time = 4.5 m/s * 2.69 s = 12.1 meters.
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
Answer:
Kepler's laws apply: First Law: Planetary orbits are elliptical with the sun at a focus. Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times. Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semimajor axis is the same for all planets.
The height of the bullet when the velocity is zero is 256 ft.
<h3>Height of the bullet when the velocity is zero </h3>
The height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;

The height of the bullet at this time is calculated as follows;

Learn more about height of projectiles here: brainly.com/question/10008919
Answer:
I think you are looking for the velocity, so the answer is 38.5 m/s
Explanation:
Velocity is giving by displacement/time. North will be positive and South will be negative, George travels 750 meters then travels -250 meters his displacement is then 750 - 250 or 500 meters. Divide that by 13 seconds to get 38.5 m/s.
Answer:
This show the most stable of atom of that element
Explanation:
The mass number of a element on the periodic table show the most stable atoms of that element.