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Nina [5.8K]
3 years ago
15

When a wave is acted upon by an external damping force, what happens to the energy of the wave

Physics
2 answers:
Rasek [7]3 years ago
8 0
The energy of the wave decreases gradually
bazaltina [42]3 years ago
3 0

Answer:

Explanation:

  The energy of the wave its determined by the mass of the fuid of the wave and the speed. The amount of motion equation P= m.v

  So according to the impulse and amount of motion theorem (ΔP= mvₙ- mv₀).

  If the wave is acted upon by an external dumping force, the wave its going to decrease his energy because the reduction of the speed and the mass.  

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What does it mean to do science
Basile [38]

Answer:

Doing science could be defined as carrying out scientific processes, like the scientific method, to add to science's body of knowledge.

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3 years ago
HELP!!! Why is plasma considered the most common state of matter in the universe?
olasank [31]

Clue : There is plasma in sun

4 0
3 years ago
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Estimate the radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 9.5 cm from the center of the bul
MA_775_DIABLO [31]

Given Information:  

Power of bulb = w = 25 W atts

distance = d = 9.5 cm = 0.095 m

Required Information:  

Radiation Pressure = ?

Answer:

Radiation Pressure =7.34x10⁻⁷ N/m²

Explanation:

We know that radiation pressure is given by

P = I/c

Where I is the intensity of radiation and is given by

I = w/4πd²

Where w is the power of the bulb in watts and d is the distance from the center of the bulb.

So the radiation pressure becomes

P = w/c4πd²

Where c = 3x10⁸ m/s is the speed of light

P = 25/(3x10⁸*4*π*0.095²)

P = 7.34x10⁻⁷ N/m²

Therefore, the radiation pressure due to a 25 W bulb at a distance of 9.5 cm from the center of the bulb is 7.34x10⁻⁷ N/m²

4 0
3 years ago
An electron at Earth's surface experiences a gravitational force of magnitude F=(9.11×10−31 kg)⋅(9.8 m/s2). Part A How far away
katrin [286]

Answer:

r = 5,085 m

Explanation:

The force exerted by on the surface of the Earth on an electron is its weight

          W = F = 9.11 10⁻³¹  9.8

          W = 8.9 10⁻³⁰ N

The electric force between an electron and a proton is given by Coulomb's Law

         Fe = k q₁ q₂ / r²

         Fe = - k q² / r²

They ask us that W = Fe

         W = k q² / r²

          r = √ k q² / W

Let's calculate

        r = √ 8.99 10⁹ (1.6 10⁻¹⁹)² /8.9 10⁻³⁰

        r = √ 25.86

        r = 5,085 m

Let's look for the relationship of this distance with the harmonic distance

        R / R_atomic = 5,085 / 10⁻¹⁰

        R / R_Atomic = 5 10¹⁰

We see that this distance is 10¹⁰ times the interatomic distance, so the gravitational attraction force is very small at atomic scale

8 0
3 years ago
If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of t
vesna_86 [32]

Average velocity is found by the following formula:


v_{average} =  \frac{v_f+v_i}{2}


v_i = 13 \\ v_f = 30 \\ v_{average} =  \frac{30+13}{2} =  \frac{43}{2} = 21.5  \frac{m}{s}

3 0
3 years ago
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