F(x)=10-16/x
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
4∈[2,8] is the required point.
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
4∈[2,8] is the required point.
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Answer:
a) θ = b) r = 31.27 inch
Step-by-step explanation:
(a)
area of sector: * r² * θ
384 = * r² * θ
384 = * (24)² * θ
θ = 384/288
θ =
(b)
384 = * r² *
r² = 384 * 2 *
r² = 977.848
r = √977.848
r = 31.27 inch