¿Cual es el perímetro de un hexágono regular cuyo lado mide 16,5cm?

Mercedes has a spool containing 15 2/3 inches of ribbon she cut a length of 6 1/2 inch to tie a bow how much ribbon is left on t

Blizzard [7]

Answer: The answer is...

9 1/6

Step-by-step explanation:

Subtract the fractions by first finding a common denominator. Then, write equivalent fractions, subtract the whole numbers and the numerators. Write the answer in simplest form.

15 2/3- 6 1/2

15 4/6 - 6 3/6= 9 1/6

Mercedes has 9 1 /6 inches of ribbon left.

I hope yo have a productive day

6 0

4 years ago

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Evaluate the expression 3 4/5 x - 2 1/2 for x = -10

daser333 [38]

the answer to this problem u asked the answer for is ... -19/15

7 0

4 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately 923.558 m²

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ 923.558 m²

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago

You have 42 coins with a total value of $3.00. Some of the coins are dimes, and the rest are quarters.

nlexa [21]

Answer:

1. $3.00+42=$3.42

2. 4 Dimes , 2 Pennies

Step-by-step explanation:

2. 4 Dimes = 40 cents , 2 pennies = 2 cents

1. Add up 3.00+42 and that is how you could get the answer for number 1 .

6 0

3 years ago

Given the following triangles, what additional information is required in order to know that the triangles are congruent because

Soloha48 [4]

Answer:

The correct answer is : DCQ ( angle) = DCE (angle)

8 0

4 years ago

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