¿Cual es el perímetro de un hexágono regular cuyo lado mide 16,5cm?

Mathematics

1 answer:

alukav5142 [94]3 years ago

6 0

Step-by-step explanation:

6(16.5 cm) = 99 cm

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PLEASSEEEEEE HELPPPPPP! WILL GIVE BRAINLIEST.

4vir4ik [10]

First replace x and y by 3 and 4.

(3*(x)+1)/(4*(y)^2)

((3*(3))+1)/(4*((4)^2)) = (9+1)/(4*16) = 10/64 = 5/32.

5/32 is your answer.

Please mark me as brainliest!

3 0

3 years ago

Solve for x.

Nonamiya [84]

$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\text{use distributive property}\\\\-\dfrac{2}{\not3_1}\cdot\not3^1x+\dfrac{8}{3}+3x=\dfrac{5}{6}\\\\-2x+3x+\dfrac{8}{3}=\dfrac{5}{6}\ \ \ \ |-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8\cdot2}{3\cdot2}\\\\x=\dfrac{5}{6}-\dfrac{16}{6}\\\\\boxed{x=-\dfrac{11}{6}}$

Other method:

$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\cdot6\\\\2(-2)(3x-4)+18x=5\\\\-4(3x-4)+18x=5\ \ \ \ |\text{use distributive property}\\\\-12x+16+18x=5\ \ \ \ |-16\\\\6x=-11\ \ \ \ |:6\\\\\boxed{x=-\dfrac{11}{6}}$