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Irina18 [472]
3 years ago
8

Compare how entropy changes for the following two systems:

Chemistry
1 answer:
postnew [5]3 years ago
7 0

System A undergoes an increase in entropy while system B undergoes a decrease in entropy.

Entropy is the degree of disorderliness of a system. The entropy of a system depends on the number of particles present in the system as well as the state of matter.

Entropy is increased when solid particles dissolve in water because more particles are produced thereby increasing the level of disorderliness in the system.

On the other hand, when vapor is condensed, the degree of disorderliness decreases as gases are converted to liquids.

Learn more: brainly.com/question/13146879

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what is the pH of a solution that results when 0.010mol HNO3 is added to 500.ml of a solution that is 0.10M in aqueous ammonia a
WARRIOR [948]

Answer : The  

pH of a solution is, 8.56

Explanation : Given,

K_b=1.8\times 10^{-5}

Concentration of ammonia (base) = 0.10 M

Concentration of ammonium nitrate (salt) = 0.55 M

First we have to calculate the value of pK_b.

The expression used for the calculation of pK_b is,

pK_b=-\log (K_b)

Now put the value of K_b in this expression, we get:

pK_b=-\log (1.8\times 10^{-5})

pK_b=5-\log (1.8)

pK_b=4.7

Now we have to calculate the pOH of buffer.

Using Henderson Hesselbach equation :

pOH=pK_b+\log \frac{[Salt]}{[Base]}

Now put all the given values in this expression, we get:

pOH=4.7+\log (\frac{0.55}{0.10})

pOH=5.44

The pOH of buffer is 5.44

Now we have to calculate the pH of a solution.

pH+pOH=14\\\\pH+5.44=14\\\\pH=14-5.44\\\\pH=8.56

Thus, the pH of a solution is, 8.56

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