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ryzh [129]
2 years ago
6

The thermometer in the

Chemistry
1 answer:
const2013 [10]2 years ago
7 0

Answer:

The thermometer in the [black] paper shows the greatest increase in temperature because black [absorbs] all wavelengths of visible light. The thermometer in the [white] paper shows the smallest increase in temperature because white [reflects] all colors of visible light. The thermometers in the green, red, and blue paper all show an increase in temperature. However, they don't increase as much as the thermometer in the black paper because these colors [absorb all other colors and reflect their own color.]

Explanation:

Hope this helps you understand!

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DochEvi [55]

Answer:

sorry i dont know this question answer but please maek me as brilliant

6 0
2 years ago
What is the mass, in grams, of one mole of any substance known as?
Elena-2011 [213]

Answer: molar mass

Explanation:

The molar mass of any substance is it's relative molecular mass expressed in grams. Hence, the relationship between molar mass of any substance and mass, in grams, of one mole of any substance is mathematically expressed as:

Number of moles =

(Mass in grams ➗ Molar mass)

Hence, the unit of molar mass is gram per mole (g/mol)

Thus, molar mass is the answer.

3 0
3 years ago
If water with a mass of 25.0 grams freezes in a closed system such as a closed glass jar, what is the mass of the formed ice aft
uranmaximum [27]
The mass would still be the same 25.0 g but the volume would be bigger
3 0
2 years ago
Nitric oxide reacts with chlorine to form nocl. the data refer to 298 k. 2no(g) + cl2(g) → 2nocl(g) substance: no(g) cl2(g) nocl
tigry1 [53]

Answer:

- 10.555 kJ/mol.

Explanation:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

Where, ∆G°rxn is the standard free energy change of the reaction (J/mol).

∆H°rxn is the standard enthalpy change of the reaction (J/mol).

T is the temperature of the reaction (K).

∆S°rxn is the standard entorpy change of the reaction (J/mol.K).

  • Calculating ∆H°rxn:

∵ ∆H°rxn = ∑∆H°products - ∑∆H°reactants

<em>∴ ∆H°rxn = (2 x ∆H°f NOCl) - (1 x ∆H°f Cl₂) - (2 x ∆H°f NO) </em>= (2 x 51.71 kJ/mol) - (1 x 0) - (2 x 90.29 kJ/mol) = - 77.16 kJ/mol.

  • Calculating ∆S°rxn:

∵  ∆S°rxn = ∑∆S°products - ∑∆S°reactants

<em>∴ ∆S°rxn = (2 x ∆S° NOCl) - (1 x ∆S° Cl₂) - (2 x ∆S° NO) </em>= (2 x 261.6 J/mol.K) - (1 x 223.0 J/mol.K) - (2 x 210.65 J/mol.K) =<em> - 121.1 J/mol.K. = - 0.1211 kJ/mol.K.</em>

<em></em>

  • Calculating ∆G°rxn:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

<em>∴ ∆G°rxn = ∆H°rxn - T∆S°rxn </em>= (- 77.16 kJ/mol) - (550 K)(- 0.1211 kJ/mol.K) = <em>- 10.555 kJ/mol.</em>

4 0
3 years ago
The ksp of pbi2 is 1.4 x 10-8. what is the molar solubility of lead(ii iodide in a solution of 0.400 m sodium iodide?
tino4ka555 [31]
The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:

PbI2 = Pb^2+ + 2I-

We solve as follows:

Ksp = [Pb2+][I-]^2 = <span>1.4 x 10-8
</span><span>1.4 x 10-8 = x(2x)^2
</span><span>1.4 x 10-8 = 4x^3
x = 1.5x10^-3 M

The molar solubility would be </span>1.5x10^-3 M.
8 0
2 years ago
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