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2 years ago

The thermometer in the

Chemistry

1 answer:

const2013 [10]2 years ago

7 0

Answer:

The thermometer in the [black] paper shows the greatest increase in temperature because black [absorbs] all wavelengths of visible light. The thermometer in the [white] paper shows the smallest increase in temperature because white [reflects] all colors of visible light. The thermometers in the green, red, and blue paper all show an increase in temperature. However, they don't increase as much as the thermometer in the black paper because these colors [absorb all other colors and reflect their own color.]

Explanation:

Hope this helps you understand!

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In Experiment #6 you learned that Zn will dissolve in acidic aqueous solutions as Zn2+, but Cu will not dissolve because Cu is l

Gala2k [10]

Answer:family fdhdfgfdsh

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3 years ago

In the relationship between ΔG and K for a given reaction, if ΔG is negative, what is K? K is equal to 0. K is equal to 1. K is

frutty [35]

K is greater than 1. #platolivesmatter

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3 years ago

Read 2 more answers

Based on the molecular formula, determine whether each compound is an alkane, alkene, or alkyne. (Assume that the hydrocarbons a

topjm [15]

Answer:

a. alkyne

b. alkane

c. alkyne

d. alkene

Explanation:

The general formula for each class of compound is given below

Alkane: $C_nH_{2n+2}$

Alkene: $C_nH_{2n}$

Alkyne: $C_nH_{2n-2}$ (assuming single multiple bonds)

Now let us classify according to the above formulas:

a. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne

b. It has two hydrogen atoms more than the two times of carbon atoms hence, it's alkane

c. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne

d. It has hydrogen atoms two times of carbon atoms hence, it's alkene

5 0

3 years ago

Read 2 more answers

What is the entropy change in the environment when 5.0 MJ of energy is transferred thermally from a reservoir at 1000 K to one a

Leni [432]

Answer:

The entropy change in the environment is 3.62x10²⁶.

Explanation:

The entropy change can be calculated using the following equation:

$\Delta S = \frac{Q}{k_{B}}(\frac{1}{T_{f}} - \frac{1}{T_{i}})$

Where:

Q: is the energy transferred = 5.0 MJ

$k_{B}$ : is the Boltzmann constant = 1.38x10⁻²³ J/K

$T_{i}$ : is the initial temperature = 1000 K

$T_{f}$ : is the final temperature = 500 K

Hence, the entropy change is:

$\Delta S = \frac{5.0 \cdot 10^{6} J}{1.38 \cdot 10^{-23} J/K}(\frac{1}{500 K} - \frac{1}{1000 K}) = 3.62 \cdot 10^{26}$

Therefore, the entropy change in the environment is 3.62x10²⁶.

I hope it helps you!

7 0

3 years ago

Which of the following molecules would you expect to have a dipole moment of zero? a,CH2 Ch3

Vadim26 [7]

Answer: The molecule $CH_{3}-CH_{3}$ is expected to have a dipole moment of zero.

Explanation:

The product of magnitude of the charge calculated in electrostatic units is called dipole moment.

Formula for dipole moment is as follows.

Dipole moment = Charge (in esu) $\times$ distance (in cm)

Non-polar molecules have zero dipole moment.

For example, $CH_{3}-CH_{3}$ is a non-polar molecule so its dipole moment is zero.

$H_{2}C=O$ is a polar molecule so it will have dipole moment.

$CH_{2}Cl_{2}$ is a polar molecule so it will have dipole moment.

$NH_{3}$ has nitrogen atom as more electronegative than hydrogen atom. So, net dipole moment will be in the direction of nitrogen atom.

Thus, we can conclude that the molecule $CH_{3}-CH_{3}$ is expected to have a dipole moment of zero.

4 0

3 years ago