Question

What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg?

Answer 1

Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 2300 mm Hg = 3.02 atm  (760mmHg=1atm)

V = Volume of gas = 15 L

n = number of moles = 0.6

R = gas constant =$0.0821Latm/Kmol$

T =temperature = ?

$T=\frac{PV}{nR}$

$T=\frac{3.02atm\times 15L}{0.0821Latm/K mol\times 0.6mol}=920K$

Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K