This is stoichiometry question which involves unit conversions. We are given the fact that 1.75mol of H2 is the limiting reagent as it is the reactant which is used up entirely with excess in the other reactant remaining.
Now we establish a ratio in how the limiting reactant relates to the product:
Every 3mol H2 reacts to produce 2mol NH3. Thus, the ratio is:
3mol H2 : 2mol NH3
Use this ratio now:
(1.75mol H2) * (2/3) = 1.17mol NH3 produced.
Answer:
1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C
Explanation:
Crayon is paraffin wax. The specific heat of paraffin wax is 2.14 J/g°C
As we know
Where
is the change in temperature
m is the mass of the object
c is the specific heat in J/g°C
Substituting the given values, we get -
Joules
1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C
Answer:
Explanation:
Hello,
In this case, the weak ionization reaction for formic acid is:
In such a way, we simply recall the law of mass action in order to represent the weak ionization constant, Ka, for such process, by taking into account that the concentration of products is divided over the concentration of reactants as shown below:
Best regards.
Answer:
Weigh less than 61.9 g
Explanation:
The symbol V represents the element Vanadium and He represents Helium.
Generally, 1 mol of any atom contains 6.022 * 10^23 atoms. This means we have to find the number of moles of each elements.
For V;
Number of moles = Mass / Molar mass = 61.9 / 50.94 = 1.215 mol
1 mol = 6.022 * 10^23 atoms
1.215 = x
Number of atoms = 6.022 * 10^23 * 1.215 =7.317 * 10^23
For He;
Since equal number of moles contain equal number of atoms;
Number of mol of He = 1.215 mol
Number of moles = Mass / Molar mass
Mass = Molar mass * Number of moles = 4 * 1.215 = 4.86 g
This means it would weigh less.