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Olegator [25]
3 years ago
7

Exactly 15.0 g of a substance can be dissolved in 150.0 g of water what is the solubility of the substance in grams per 100 g of

water
Chemistry
1 answer:
Leokris [45]3 years ago
5 0
<span>(15.0 g) / (150.0 g) x (100 g) = 10.0 g/100 g H2O </span>
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12) A 17.92 g sample of copper was submerged in water, and the volume reading rose by 2.00 mL. What is the density of the copper
emmasim [6.3K]

Hey there!:

Mass = 17.92 g

Volume = 2.00 mL

Density =  ??

Therefore:

D = m / V

D = 17.92 / 2.00

D = 8.96 g/mL

Hope this helps!

3 0
3 years ago
A moist red litmus paper is used for testing ammonia gas ,why​
yawa3891 [41]

Answer:

when the red litmus paper is placed in a jar of ammonia, the red litmus paper turns into blue as ammonia gas is basic in nature. It confirms the alkalinity of the ammonia gas.

6 0
3 years ago
Sewage is a liquid waste which causes<br> _________ and ________ pollution.
nadezda [96]

Answer:

Lake and River pollution?

Explanation:

5 0
3 years ago
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Which unit is used for measuring atomic mass? A. atomic mole B. grams/mole C. grams D. atomic mass unit E. atomic mass weight
mihalych1998 [28]

The atomic mass is defined as the mass an atom of an element. The atomic mass in approximation is equal to the sum of number of neutrons and protons in the nucleus of an atom (mass number). The units which are used for measuring the atomic mass is atomic mass unit, u.

Thus, the correct option is option E that is atomic mass unit is used for measuring atomic mass.

7 0
3 years ago
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Hc2h3o2(aq)+h2o(l)⇌h3o+(aq)+c2h3o−2(aq) kc=1.8×10−5 at 25∘c part a if a solution initially contains 0.260 m hc2h3o2, what is the
Cloud [144]

Answer : The equilibrium concentration of H_3O^+ at 25^oC is, 2.154\times 10^{-3}m.

Solution : Given,

Equilibrium constant, K_c=1.8\times 10^{-5}

Initial concentration of HC_2H_3O_2 = 0.260 m

Let, the 'x' mol/L of H_3O^+ are formed and at same time 'x' mol/L of HC_2H_3O_2 are also formed.

The equilibrium reaction is,

                  HC_2H_3O_2(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+C_2H_3O_2^-(aq)

Initially                0.260 m                       0                 0

At equilibrium    (0.260 - x)                     x                 x

The expression for equilibrium constant for a given reaction is,

K_c=\frac{[H_3O^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

Now put all the given values in this expression, we get

1.8\times 10^{-5}=\frac{(x)(x)}{(0.260-x)}

By rearranging the terms, we get the value of 'x'.

x=2.154\times 10^{-3}m

Therefore, the equilibrium concentration of H_3O^+ at 25^oC is, 2.154\times 10^{-3}m.

4 0
3 years ago
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