Explanation:
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The weather instruments: rain gauge can measure the amount of snow fall True or false
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The steel would have a mass of 78g and the mercury would have a mass of 68g. So the Steel has greater mass.
Explained: This picture I also attached explains that whenever you have an equation dealing with density and volume alone, you will multiply the 2 together to get your answer for mass. And when your dealing with mass and rather volume or density you will divide the mass by whatever the volume or density is. For example if you need to find the density of an object that is 25g and 14ml you will write out this equation 25g/14ml= 1.78 g/ml. And if you need to find the mass of an object that is 27ml and 14g/ml you will write an equation like this 27mlX14g/ml= 378g. I hope this helps with your understanding.
Explained: This picture I also attached explains that whenever you have an equation dealing with density and volume alone, you will multiply the 2 together to get your answer for mass. And when your dealing with mass and rather volume or density you will divide the mass by whatever the volume or density is. For example if you need to find the density of an object that is 25g and 14ml you will write out this equation 25g/14ml= 1.78 g/ml. And if you need to find the mass of an object that is 27ml and 14g/ml you will write an equation like this 27mlX14g/ml= 378g. I hope this helps with your understanding.
The time taken for Hydrogen-3 to decay from 88 g to 11 g is 36.9 years.
<h3>Half-life:</h3>This can be defined as the time taken for half the sample of a substance to decay or disintegrate
To calculate the time it will take Hydrogen to decay from 88g to 11 g we use the formula below.
Formula:
- R = R'(
)................ Equation 1
Where:
- R = Original sample of Hydrogen
- R' = Sample of Hydrogen left after decay
- T = Total time of decay
- n = Half-life of hydrogen.
From the question,
Given:
- R = 88 g
- R' = 11 g
- n = 12.3 years.
Substitute these values into equation 1
- 88 = 11(
)
Solve for T.
Equating the base in equation 2 above,
- T/12.3 = 3
- T = 12.3×3
- T = 36.9 years.
Hence, the time taken for Hydrogen-3 to decay from 88 g to 11 g is 36.9 years
Learn more about half-life here: brainly.com/question/11152793