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leonid [27]
3 years ago
10

A rolling ball has an initial velocity of 1.6 meters per second. if the ball has a constant acceleration of 0.33 meters per seco

nd squared in the same direction as its movement, what is its velocity after 3.6 seconds?
Physics
1 answer:
lukranit [14]3 years ago
7 0
We have:

Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
Time (t) = 3.6 sec

There are five constant acceleration equations that would help us to find the velocity:

v=u+at
s=ut+ \frac{1}{2}at^2
s= \frac{1}{2}(u+v)t
v^2=u^2+2as
s=vt- \frac{1}{2}at^2

Since we have u, a, t and we want v
We will use the first formula v=u+at

v=1.6+(0.33)(3.6)
v= 2.788 m/s
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