The amount of space an objective takes up measures by volume.
<u>Explanation:</u>
Volume is a proportion of the measure of space, unfilled column that a substance or an item takes up. The essential SI unit to volume denotes in the (cubic meter), yet volumes might be estimated in cubic centimetres, and fluids might be estimated in liters (L) or milli-liters (mL). How the volume of matter is estimated relies upon its state. The fluid's volume is estimated with an estimating holder, for example, an estimating cup or graduated chamber.
The gas volume relies upon the volume of its holder: gases able to occupy anything that space is accessible to them. The occupied space of a routinely molded strong can be determined from its measurements. For instance, the rectangle’s volume strong is the result of its width, length, and stature. The volume of a sporadically molded strong can be estimated by the uprooting technique.
<span>The latitude 20 degrees north and longitude 65 degrees west is in the Atlantic Ocean, north of Puerto. The north coast region of Puerto Rico named "Porta Atlantico" faces the dark blue Atlantic Ocean. On the off chance that you long for unwinding on a tranquil shoreline, losing all sense of direction in the magnificence of waves smashing, and being calmed by their song, you might need to remain on the north drift, lease an auto and investigate.</span>
The 'strength' of the electric field is the force on 1C of charge at that point.
At this 'certain location', the field is 40/5 = 8 newtons per coulomb = <u>8 volts</u>
Answer:
0.82 mm
Explanation:
The formula for calculation an 
bright fringe from the central maxima is given as:
so for the distance of the second-order fringe when wavelength 
= 745-nm can be calculated as:
where;
n = 2
= 745-nm
D = 1.0 m
d = 0.54 mm
substituting the parameters in the above equation; we have:
= 0.00276 m
= 2.76 × 10 ⁻³ m
The distance of the second order fringe when the wavelength 
= 660-nm is as follows:
= 1.94 × 10 ⁻³ m
So, the distance apart the two fringe can now be calculated as:
= 2.76 × 10 ⁻³ m - 1.94 × 10 ⁻³ m
= 10 ⁻³ (2.76 - 1.94)
= 10 ⁻³ (0.82)
= 0.82 × 10 ⁻³ m
= 0.82 × 10 ⁻³ m 
= 0.82 mm
Thus, the distance apart the second-order fringes for these two wavelengths = 0.82 mm
