Answer:
<h2>The answer is 29.7 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
density = 2.7 g/mL
volume = 11 mL
The mass is
mass = 2.7 × 11
We have the final answer as
<h3>29.7 g</h3>
Hope this helps you
Volumen = constant => P/T = constant
T1 = 21°C + 273.15 = 294.15 k
P1 = 0.82 atm
T2 = - 3.5°C + 273.15 = 269.65 k
P2 = ?
P2 / 269.65k = 0.82atm / 294.15k
P2 = [0.82atm / 294.15k] * 269.65kg = 0.75 atm
Answer:
Option (d) chlorine has a greater ionization energy than sodium
Explanation:
Ionization energy is the energy required to remove an electron from a gaseous atom or ion. Sodium has just 1 electron in it's outmost shell and chlorine has 7.
Sodium needs 7 electrons to complete it's octet configuration and chlorine needs just 1.
Sodium can not attract 7 electrons to complete it's octet configuration instead it will easily lose the 1 electron in it's outmost shell to form cation. On the other hand, it will be difficult for chlorine to lose any of it's outmost electrons. This makes chlorine to have higher ionization energy than sodium.
According to google, one gallon equals 8.36 pounds. I took 8.36and divided by 0.00590 and got 1416.94915254 So if rounded to the nearest hundreth, 1416.95. I have no idea if I'm right. Sorry I couldn't do more!
Answer:
Explanation:
We are asked to find the specific heat capacity of a liquid. We are given the heat added, the mass, and the change in temperature, so we will use the following formula.
The heat added (q) is 47.1 Joules. The mass (m) of the liquid is 14.0 grams. The specific heat (c) is unknown. The change in temperature (ΔT) is 1.80 °C.
- q= 47.1 J
- m= 14.0 g
- ΔT= 1.80 °C
Substitute these values into the formula.
Multiply the 2 numbers in parentheses on the right side of the equation.
We are solving for the heat capacity of the liquid, so we must isolate the variable c. It is being multiplied by 25.2 grams * degrees Celsius. The inverse operation of multiplication is division, so we divide both sides of the equation by (25.2 g * °C).
The original measurements of heat, mass, and temperature all have 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 9 in the thousandth place to the right tells us to round the 6 up to a 7.
The heat capacity of the liquid is approximately 1.87 J/g°C.
