By the angle bisector theorem, one of the lengths of the third side of the triangle is given by:
1.5 / 1 = x / 2.6
x = 1.5 x 2.6 = 3.9
One of the possible length of the third side is 3.9 cm
The other possible length is given by 1 / 1.5 = x / 2.6
1.5x = 2.6
x = 2.6/1.5 = 1.7
The other possible length of the third side is 1.7 cm.
Answer:
<u>553.143 mi²</u>
Step-by-step explanation:
Surface Area (Cylinder) :
- 2πr (r + h)
- 2 x 22/7 x 8 (8 + 3)
- 16 x 22/7 x 11
- 176 x 22/7
- 3872/7
- <u>553.143 mi²</u>
Answer:
56 + 53pi
Step-by-step explanation:
<u><em>Area of small circles:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 4 / 2 = 2cm
A = pi (2cm)^2
A = pi (4cm)
A = 4pi
<u><em>Area of large circle:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 14 / 2 = 7cm
A = pi (7cm)^2
A = pi (49cm)
A = 49pi
<u><em>Area of rectangle:</em></u>
Area = width x length
Area = 14cm x 4cm
Area = 56cm
<u><em>Add all three areas:</em></u>
Area of rectangle + large circle + small circle
56cm + 49pi + 4pi = 56cm + 53pi
X(u, v) = (2(v - c) / (d - c) + 1)cos(pi * (u - a) / (2b - 2a))
y(u, v) = (2(v - c) / (d - c) + 1)sin(pi * (u - a) / (2b - 2a))
As
v ranges from c to d, 2(v - c) / (d - c) + 1 will range from 1 to 3,
which is the perfect range for the radius. As u ranges from a to b, pi *
(u - a) / (2b - 2a) will range from 0 to pi/2, which is the perfect
range for the angle. So, this maps the rectangle to R.
