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goldfiish [28.3K]
3 years ago
5

The differce of a number and twenty four is equal to forty six​

Mathematics
2 answers:
g100num [7]3 years ago
8 0

Answer:

It is 70 because when you add 24 and 46 it is 70

so when you subtract 24 from 70, you get 46

:)

Step-by-step explanation:

lisov135 [29]3 years ago
7 0

Answer:

n - 24 = 46

Step-by-step explanation:

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You are choosing between two health clubs. Club A offers membership for a fee of $ 19plus a monthly fee of $ 21.  Club B off
11111nata11111 [884]

Answer:

For 2 months

Step-by-step explanation:

Let after x months the cost of each health club is same,

Now, In club A,

Membership fees = $ 19,

Monthly fees = $ 21,

So, the total fees for x months = membership fees + total monthly fees for x months

= 19 + 21x

In Club B,

Membership fees = $ 23,

Monthly fees = $ 20,

So, the total fees for x months = membership fees + total monthly fees for x months

= 23 + 20x

Thus, we can write,

19 + 21x = 23 + 20x

21x - 20x = 23 - 21

x = 2

Hence, for 2 months the total cost of each health club would be same.

8 0
3 years ago
Solve for x x + 6=18
Verizon [17]
X=12

This is because you subtract 6 from both sides to get the x isolated.

So x=18-6

x=12 :)
6 0
3 years ago
Please help me with this!!!
Vika [28.1K]

Answer:

Step-by-step explanation:

whatheactualfuk i think its 98?

8 0
3 years ago
Use the properities to find the sum or product of 93+[68+7]
kondor19780726 [428]

Answer:

the answer for this questionis 93(68+7)

8 0
3 years ago
Please help me find limit​
cluponka [151]

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  \displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}

4 0
3 years ago
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