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rjkz [21]
2 years ago
8

HELP PLS AND THANK U FAST PLS <3

Chemistry
1 answer:
kodGreya [7K]2 years ago
3 0

Answer:

dragon fly larvae, beetles, fish, pelican

Explanation:

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For each process, predict the sign on the entropy change and write a sentence or two to explain how to make this prediction with
MrRa [10]

Answer: a. A solid melts: \Delta S=+ve

b. a vapor is converted to solid: \Delta S=-ve

c. a liquid freezes:  \Delta S=-ve

d. A solid sublimes:  \Delta S=+ve

e.  a vapor condenses to liquid :  \Delta S=-ve

f. a liquid boils:   \Delta S=+ve

g. dissolving a tablespoon of salt in water:  \Delta S=+ve

h. combustion of gasoline:  \Delta S=+ve

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy change is negative and vice versa.

a. A solid melts: The solid is converting to liquid, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

b. a vapor is converted to solid: The gas  is converting to solid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger Thus the entropy change (\Delta S) is negative.

c. a liquid freezes: The liquid is converting to solid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger. Thus the entropy change (\Delta S) is negative.

d. A solid sublimes: The solid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

e.  a vapor condenses to liquid : The gas  is converting to liquid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger. Thus the entropy change (\Delta S) is negative.

f. a liquid boils: The liquid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

g. dissolving a tablespoon of salt in water: The solid is converting to ions , thus the randomness is increasing as the ions can move freely. Thus the entropy change (\Delta S) is positive.

h. combustion of gasoline: The liquid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

6 0
2 years ago
[Gradpoint-Question AK-3] Acid is added to a beaker containing crushed marble. What effect does stirring this mixture have on th
Evgen [1.6K]
A : The number of particle collision increases
4 0
2 years ago
Read 2 more answers
Which best describes a neutralization reaction?
Softa [21]
A reaction between to acids
3 0
3 years ago
Compound A serves as a prodrug for the analgesic benzocaine. (A prodrug is a pharmacologically inactive compound that is convert
NemiM [27]

Answer:

The hydrolysis in aqueous HCl of compound A can lead to the formation of a carboxylic acid and an alcohol.

Explanation:

The picture shows the structures of compound A, benzoncaine and the possible products of the proposed reaction.

The acidic hydrolysis is the inverse of the esterification reaction. Therefore, the ester group of compund A will react to form the equivalent carboxylic acid and alcohol.

In order to form benzocaine, the hydrolysis happens in with the nitrile group.

3 0
2 years ago
A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain
sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

-w=\frac{dm}{dt}

w is the mass flow

m is the mass of salt

-v*C=\frac{dm}{dt}

v is the volume flow

C is the concentration

C=\frac{m}{V+(6-3)*L/min*t}

-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}

-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}

-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)

-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)

m=90kg*[2000L/(2000L+3*L/min*t)]

a) Initially: t=0

m=90kg*[2000L/(2000L+3*L/min*0)]=90kg

b) t=210 min (3.5 hr)

m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg

c) If time trends to infinity the  division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0
3 years ago
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