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-BARSIC- [3]
3 years ago
6

Which of these steps would most likely be part of a lab procedure?

Chemistry
1 answer:
andreev551 [17]3 years ago
9 0

Answer:

there is no steps shown here

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Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 13.2 moles of FeO?
irina [24]

The number of moles of aluminium  that are needed to react completely  with 13.2 moles of FeO  is  8.8 moles



calculation


2Al + 3FeO → 3aFe +Al2O3

by use of of mole ratio of Al: FeO  from  equation above = 2:3 the moles of  Al is  therefore

= 13.2  x  2/3=8.8  moles  of Al

3 0
3 years ago
From the list which items of ppe should always be put on first
fenix001 [56]
Where's the list? If you show it maybe I can help
4 0
3 years ago
The number of B2H6 molecules
zlopas [31]

Answer:

6.022 × 10²³ molecules of B₂H₆

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

B₂H₆ molecules:

21.63 g = one mole of B₂H₆= 6.022 × 10²³ molecules of B₂H₆

8 0
3 years ago
a gas that exerts a pressure of _____ bar in a container with a volume of 0.5650 L will exert a pressure of 715.1 bar when trans
vampirchik [111]
Boyle's law gives the relationship between pressure and volume of gases.
it states that for a fixed amount of gas at constant temperature, pressure of gas is inversely proportional to volume.
PV = k
where P - pressure , V - volume and k - constant 
P1V1 = P2V2 
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting this equation 
P x 0.5650 L = 715.1 bar x 1.204 L
P = 1 524 bar

8 0
3 years ago
What is the new volume of a sample of neon if 5.23 L of the gas, which was originally at 214 mmHg, is compressed until the press
Yuliya22 [10]

This problem can be solved using Boyle's law:p1v1=p2v2

so 5.23*214=796*v2 v2=(5.23*214)/796=1.4L

8 0
3 years ago
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