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Delvig [45]
3 years ago
14

How many moles of SnF2 will be produced along with 48 grams of H2

Chemistry
1 answer:
wolverine [178]3 years ago
5 0

Answer:

24 moles

Explanation:

given data

H_2 = 48 grams

to find out

how many moles of SnF_2 will be produced

solution

we know that Stoichiometry is here as

Sn+2HF\rightarrow SnF_2+H_2      ......................1

so we get here mole of solute H_2 that is express as

mole = \frac{\text{given mass}}{\text{Molar Mass}}      ..........................2

put here value for H_2  

mole = \frac{48}{2}  

mole of H_2 = 24 mole

and

we can say that here as per equation 1 that one mole of H_2  is go with one mole of SnF_2

so here H_2 24 mole is go with 24 moles mole of SnF_2  

so we can say SnF_2 will be produced 24 moles

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Answer:

We will need 147.772 mL of KH2PO4 to make this solution

Explanation:

For this case we can give the following equation:

H2PO4 - ⇄ H+ + HPO42-

With following pH- equation:

pH = pKa + log [HPO42-]/[H2PO4-]

7.05 = 7.21 + log [HPO42-]/[H2PO4-]

-0.16 =  log [HPO42-]/[H2PO4-]

10^-0.16 = [HPO42-]/[H2PO4-]

0.6918 = [HPO42-]/[H2PO4-]

Let's say the volume of HPO42-= x  then the volume of H2PO4- will be 250 mL - x

Since both have a concentration of 1M = 1 mol /L

If we plug this in the equation 0.6918 = [HPO42-]/[H2PO4-]

0.6918 = x / (250 - x)

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To control this we can plug this in the pH equation

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7.05= 7.21 + log (102.228 / 147.772) = 7.05

We will need 147.772 mL of KH2PO4 to make this solution

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Correct option is

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