The greatest amount of friends he can have is 7
A+b+c=130
a,b,c ip cu 2,3,4
2a=3b=4c=k
a=k/2
b=k/3
c=k/4
k/2 + k/3+ k/4= 130 aducem la acelasi numitor (12)
6k+4k+3k=1560
13k=1560
k=120
a=120/2=60
b=120/3=40
c=120/4=30
137,426.9 is 140,000 when rounded to 2 sig figs
Answer:
you gatta show the picture
Step-by-step explanation:
