Danny and his mom are building a fenced region for their dog in the backyard. The region measures 18 ft. by 27 ft. The gate they
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To start out, notice that you want the percent of voters that chose candidate A, not the percent of the class that chose candidate A.
Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying:
"number that chose candidate A" divided by "number of voters"
1) The numerator of the fraction should be the number of votes for candidate A, which is 11.
2) The denominator of the fraction should be the number of voters. You're told that "t<span>here were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
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3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
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Answer: Top right choice,
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Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying:
"number that chose candidate A" divided by "number of voters"
1) The numerator of the fraction should be the number of votes for candidate A, which is 11.
2) The denominator of the fraction should be the number of voters. You're told that "t<span>here were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
</span>
3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
----
Answer: Top right choice,
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</span>
Answer:
0.0903
Step-by-step explanation:
Given that :
The mean = 1450
The standard deviation = 220
sample mean = 1560
P(X> 1560) = P(Z > 0.5)
P(X> 1560) = 1 - P(Z < 0.5)
From the z tables;
P(X> 1560) = 1 - 0.6915
P(X> 1560) = 0.3085
Let consider the given number of weeks = 52
Mean = np = 52 × 0.3085 = 16.042
The standard deviation =
The standard deviation =
The standard deviation = 3.3306
Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.
Then;
Pr ( Y > 20) = P( z > 20)
From z tables
P(Y > 20) 0.0903