A test model for a new experimental gasoline engine does 45 J of work in one cycle for every 76 J of heat it takes in. What is t
1 answer:
Answer:
The efficiency of the engine is 59.2%.
Explanation:
We have,
Work done by the gasoline engine is 45 J and the for every 76 J of heat it takes in.
It is required to find the efficiency of the engine. Efficiency of the engine is given by the ratio of work done to the heat taken i. Its formula is given by :
So, the efficiency of the engine is 59.2%.
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Answer:
P₀ = 5.76 x 10⁻² MW
Explanation:
given,
efficiency of the power plant = 32%
Power produced by the nuclear fission = 0.18 MW
the power plant output = ?
using formula of efficiency
where P is the power produced in the power plant
P₀ is the power output of the power plant
P₀ = 0.18 x 0.32
P₀ = 0.0576 MW
P₀ = 5.76 x 10⁻² MW
Power plant output is equal to P₀ = 5.76 x 10⁻² MW
Answer
given,
SAT is 500 with a standard deviation of 100.
a sample of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511.
sample mean =
=
= 5
95% confidence level is achieved within +/- 1.960 standard deviations.
1.960 standard deviations x 5 is equal to +/- 9.8
confidence interval = 511 - 9.8 --- 511 + 9.8
= 501.2-----520.8
Answer:
The system's Mean Time to Failure is 1,041. hours
Explanation:
The number of independent identical motors = 4
The failure rate of each motor, λ = 0.002 failures per hour
Given that in order for the system to work, at least one of the motors must operate, therefore, the system are in parallel
The Mean Time to Failure for a parallel system of four identical components is given as follows;
Which gives;
The system's Mean Time to Failure = 1,041. hours.