X=time of the third person it would take to fill the pool
We can suggest this equation:
6[(1/20) + (1/15) +(1/x)]=1
6[(3x+4x+60)/60x]=1
(7x+60)/10x=1
7x+60=10x
7x-10x=-60
-3x=-60
x=-60/-3
x=20
Answer: the third person alone would fill the pool in 20 hours .
The full answer would be 83.454 but you can just say 83 pounds. Both are right
Answer:
112.569 ( D )
Step-by-step explanation:
Applying the estimated Regression Equation
y = b1X1 + b2X2 + a
b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884
b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925
a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252
y = 0.939X1 + 0.309X2 + 31.733
For x1 ( age ) =39, and x2(weight) =143
y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569
where
Sum of X1 = 981
Sum of X2 = 3102
Sum of Y = 2388
Mean X1 = 61.3125
Mean X2 = 193.875
Mean Y = 149.25
attached is the Tabular calculation of the required values needed for estimated regression equation
Terrorism caused 9/11... it is hands down that simple
The bearing of the individuals from each other are as indicated below;
- S45°E
- N25°E
- S65°E
- S15°E
- N45°E
- N75°E
<h3>What is bearing of Henley from Dinder?</h3>
It follows from the task content that the bearing of the individuals from each other are expected to be determined.
a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.
b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.
c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.
d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.
e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.
f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.
Read more on bearing;
brainly.com/question/23427938
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