How many moles in 206.91 g Na
1 answer:
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Answer:
46.761g/mol
Explanation:
Given parameters:
Element = Hilarium , Hi
Isotopes: Hi- 45, Hi-46 and Hi- 48
Natural abundance of Hi-45 = 18.3%
Hi-46 = 34.5%
Hi-48 = 47.2%
Unknown:
Atomic weight of naturally occurring Hilarium = ?
Solution:
Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.
We can use the expression below to find this value:
Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈
m is the atomic mass of each isotope and α is the abundance
Atomic weight = (45 x ) + (46 x
) + (48 x
)
Atomic weight of Hi = 8.235 + 15.870 + 22.656 = 46.761g/mol
The attraction of an ion leads to the formation of an ionic bond with
Ionic bond, also called an electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound.
Since the question asking among all these options:
(a) The attraction of a noble gas
(b) The attraction of a ion
(c) The attraction of a group 1 element
(d) The attraction of a ion
An ionic bond can be formed after two or more atoms lose or gain electrons to form an ion. Ionic bonds occur between metals, losing electrons, and nonmetals, gaining electrons.
Hence, option D is correct.
Learn more about the ionic bond here:
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