7 lies betwee the 2 square integers 16 and 25.
Answer:
y=-1/3x+9
Step-by-step explanation:
You would need to use the pythagorean theorum which is would be 8 squared +x squared = 15 squared
Given:
Base of a right triangle = 7 in
Height of a right triangle = a
Hypotenuse = 16 in
To find:
The length of side a.
Solution:
Using Pythagoras theorem:
In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.
![7^2+a^2=16^2](https://tex.z-dn.net/?f=7%5E2%2Ba%5E2%3D16%5E2)
![49+a^2=256](https://tex.z-dn.net/?f=49%2Ba%5E2%3D256)
Subtract 49 from both sides.
![49+a^2-49=256-49](https://tex.z-dn.net/?f=49%2Ba%5E2-49%3D256-49)
![a^2=207](https://tex.z-dn.net/?f=a%5E2%3D207)
Taking square root on both sides, we get
a = 14.4
The length of side a is 14.4 in.