<u>Answer:</u> The heat required for the process is 4.24 kJ
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Given mass of benzene = 24.8 g
Molar mass of benzene = 78.11 g/mol
Putting values in above equation, we get:
![\text{Moles of benzene}=\frac{24.8g}{78.11g/mol}=0.318mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20benzene%7D%3D%5Cfrac%7B24.8g%7D%7B78.11g%2Fmol%7D%3D0.318mol)
To calculate the enthalpy change of the reaction, we use the equation:
![\Delta H_{rxn}=\frac{q}{n}](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5Cfrac%7Bq%7D%7Bn%7D)
where,
= amount of heat absorbed = ?
n = number of moles = 0.318 moles
= enthalpy change of the reaction = 30.7 kJ/mol
Putting values in above equation, we get:
![30.7kJ/mol=\frac{q}{0.318mol}\\\\q=(30.7kJ/mol\times 0.318mol)=4.24kJ](https://tex.z-dn.net/?f=30.7kJ%2Fmol%3D%5Cfrac%7Bq%7D%7B0.318mol%7D%5C%5C%5C%5Cq%3D%2830.7kJ%2Fmol%5Ctimes%200.318mol%29%3D4.24kJ)
Hence, the heat required for the process is 4.24 kJ