The products are on the right side of the equation. For this one it would be 2AlPO4 + 3CaSO4
Answer:
31.7 °C
Explanation:
Charles law states that for volume of a gas is directly proportional to the absolute temperature for a fixed amount of gas at constant pressure
we can use the following equation
V1/T1 = V2/T2
where V1 is volume and T1 is temperature at first instance
V2 is volume and T2 is temperature at second instance
temperature should be in kelvin scale
T1 - 0 °C + 273 = 273 K
substituting the values in the equation
22.4 L / 273 K = 25.0 L / T2
T2 = 304.7 K
temperature in celcius is - 304.7 K - 273 = 31.7 °C
the gas must be 31.7 °C to reach a volume of 25.0 L
Answer:
c. KBr
.
Explanation:
Hello!
In this case, since electrolytes are substances that are able to carry electric current in the form of electrons via ions, those that are ionic are said to have the greatest capacity to conduct the electricity; in such a way, since SO2, C6H12O6 and CO are non-ionic molecules but covalent, they are not good conductor, therefore the best conductor would be c. KBr
as it is an ionic compound due to the electronegativity of the K-Br bond.
Best regards!
Answer:
Hello - this is Mrs. Gussman, your chemistry teacher. I wrote this exam question and posting it online is a violation of the academic integrity policy. Remove this post immediately.
Explanation:
solution:
Physical properties describe how a material looks. such as color, state of matter, shininess, Other physical properties include density, mp, bp, brittleness, malleability, conductivity, ductility, solubility in water. A physical property can be determined without changing the identity of the material.
Chemical properties describe how a material behaves.such as does it burn, does it corrode, does it react with air, does it react with water, does it act like a metal by giving away electrons o like a nonmetal by taking electrons, what type of bonds will it form, or is it inert, is it acidic or basic, Chemical properties can only be determined during a chemical reaction.