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bija089 [108]
3 years ago
5

I beg you to solve this for me i should submit it tomorrow ​

Physics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:do u have a text book so i can see

Explanation:

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a cyclist applies a constant forward force of 20 N to maintain a velocity 2.5 m/s. how much power does the cyclist deliver?
forsale [732]

The power exerted by the cyclist is determined as 50 W.

<h3>Average power exerted by the cyclist</h3>

The power exerted by the cyclist is calculated as follows;

P = FV

where;

  • F is the applied force
  • V is velocity

P = 20 x 2.5

P = 50 W

Thus, the power exerted by the cyclist is determined as 50 W.

Learn more about power here: brainly.com/question/25263760

#SPJ1

4 0
2 years ago
Un reloj de péndulo de largo L y período T, aumenta su largo en ΔL (ΔL &lt;&lt; L). Demuestre que su período aumenta en: ΔT = π
Kruka [31]

Answer:

 ΔT = \pi \ \frac{\Delta L}{\sqrt{Lg} }

Explanation:

In a simple harmonic motion, specifically in the simple pendulum, the angular velocity

          w = \sqrt{\frac{g}{L} }

angular velocity and period are related

          w = 2π / T

we substitute

          2π / T = \sqrt{\frac{g}{L} }

          T = 2\pi  \ \sqrt{\frac{L}{g} }

In this exercise indicate that for a long Lo the period is To, then and increase the long

          L = L₀ + ΔL

we substitute

           T = 2\pi  \ \sqrt{\frac{L + \Delta L}{g} }

            T = 2\pi  \ \sqrt{\frac{L}{g} } \ \sqrt{1+ \frac{\Delta L}{L} }

in general the length increments are small ΔL/L «1, let's use a series expansion

           \sqrt{1+ \ \frac{\Delta L}{L} } = 1 + \frac{1}{2} \frac{\Delta L}{L} + ...  

we keep the linear term, let's substitute

           T = 2\pi  \ \sqrt{\frac{L}{g} } \ ( 1 + \frac{1}{2} \frac{\Delta L}{L}  )  

if we do

           T = T₀ + ΔT

           

           T₀ + ΔT = 2\pi  \sqrt{\frac{\Delta L}{g} }  + \pi  \ \sqrt{\frac{L}{g} } \ \frac{\Delta L}{L}

            T₀ + ΔT = T₀ + \pi  \sqrt{\frac{1}{Lg} } \ \Delta L

            ΔT = \pi \ \frac{\Delta L}{\sqrt{Lg} }

4 0
3 years ago
The heating curve of an ice-water mixture that is slowly heated to 125°C contains three sloped and two level portions. What do t
marin [14]

Answer:

Explanation:

Hi there,

To get started, please recall what heating curves are, latent heat, and enthalpy of phase changes (vaporization, fusion).

In a heating curve for ice water, temperature is the dependent variable (y-axis) and heat or time elapsed is independent variable (x-axis). There are three sloped portions. These sloped portions are showing where the <u>mixture is not changing phase, and is in a specific phase.</u> (solid first, then liquid then gas).

The reason is because the addition of more heat in time is causing the temperature to rise, so the mixture is getting "hotter." The temperature is still rising, yet the mixture is still in the current phase (depending on where you are referencing on the curve).

The two leveled portions are the process of melting (first leveled) and boiling (second leveled). The reason they are horizontal is because the addition of heat is not causing temperature to go up. The molecules are in the process of distributing heat in a different form by changing the mixtures entire structure (AKA phase), and so they are flat because the average kinetic energy from heat is being used change phase.

If you liked this solution, hit Thanks or leave a Rating!

thanks,

7 0
3 years ago
Read 2 more answers
The ventilation fan of the bathroom has a volumetric flow rate of 1,640 L/s. If the air density is 1.28 kg/m3, calculate the mas
liq [111]

Answer:

7557120 kg/hour

Explanation:

Given data;

Volume of air in one second = 1640 L

Density of air = 1.28 kg/L

Mass of air in 1 hour =?

Since mass = density × volume

==> Mass of air in one second = 1.28 ×1640 = 2099.2 kg

==> Mass of air in one minute = 2099.2×60=125952 kg

==> Mass of air in one hour = 125952× 60 = 7557120 kg

So rate of flow of air is 7557120 kg/hour

5 0
4 years ago
if a man hits a golf ball (0.2 kg) which accelerates at a rate of 20 m/s squared. what amount of force acted on the ball?
kkurt [141]

F = ma

We have mass = 0.2kg

and acceleration = 20 m/s^2

So..

F = (0.2)(20)

F = 4 N

6 0
3 years ago
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