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SpyIntel [72]
3 years ago
10

A sector of circle C shown below has a radius of 6 centimeters and a central angle that measures 80 degrees. Which expression be

low correctly calculates the area of this sector in square centimeters
Mathematics
1 answer:
777dan777 [17]3 years ago
6 0

Answer:

The area of the sector is 8*pi cm² or 25.13272 cm².

Step-by-step explanation:

In order to calculate the area of a circular sector we can apply a rule of three in such a way that the circle's area, pi*r²  cm², is related to 360º in such a way that "x" cm² is related to the angle of the sector. We have:

pi*r² cm² ---------> 360º

x cm² ------------> 80º

pi*r²/x = 360/80

360*x = 80*pi*r²

x = 80*pi*r²/360

x = 80*pi*(6)²/360

x = 80*pi*36/360

x = 8*pi cm²

The area of the sector is 8*pi cm² or 25.13272 cm².

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Fantom [35]

Answer:

120

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do u do 2 over 3 =A over 60 PLZ NO LINKS THANKS
Ivanshal [37]

Hey there!

2/3 = a/30

First: you have to CROSS MULTIPLY the given numbers

2(30) = 3(a)

2(30) = 60

3(a) = 3a

New EQUATION: 3a = 60

Second: DIVIDE 3 to BOTH SIDES

3a/3 = 60/3

CANCEL out: 3/3 because that gives you 1

KEEP: 60/3 because that helps you solve for your a-value

60/3 = a

60/3 = 20

Therefore, your answer is: a = 20

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

6 0
2 years ago
How do you use numerical expressions to solve real world problems
Sonja [21]
Ask your teacher .... no kidding but really just convert the numbers 
4 0
3 years ago
A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0
3 years ago
2x + 12 = 1/3 (7/3x+4/3)
gladu [14]

Answer:

Step-by-step explanation:

2x + 12 = 1/3 (7/3x+4/3)

2x+12=\frac{1}{3}*\frac{7x}{3}+\frac{1}{3}*\frac{4}{3}\\\\2x+12=\frac{7x}{9}+\frac{4}{9}\\\\2x-\frac{7x}{9}=\frac{4}{9}-12\\\\\frac{2x*9}{1*9}-\frac{7x}{9}=\frac{4}{9}-\frac{12*9}{1*9}\\\\\frac{18x}{9}-\frac{7x}{9}=\frac{4}{9}-\frac{108}{9}\\\\\frac{18x-7x}{9}=\frac{4-108}{9}\\\\\frac{11x}{9}=\frac{-104}{9}\\\\\\x=\frac{-104*9}{11*9}=\frac{-104}{11}=-9\frac{5}{11}

8 0
3 years ago
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