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3 years ago

Why is it so hard to graduate?

1 answer:

4 0

It is hard to graduate because it is a level of understanding how to graduate......you basically have to put effort in to your work or else you fail

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S Assume you have a battery of emf E and three identical lightbulbs, each having constant resistance R. What is the total power

slega [8]

The total power delivered by the battery if the lightbulbs are connected is 9V^2/R

<h3>Power of a battery</h3>

The formula for calculating the power of a battery is expressed according to the equation;

Power = v^2/RT

where

R is the total resistance

v is the voltage or emf

If there are 3 identical lightbulbs, each having constant resistance R, then;

1/RT = 1/R + 1/R + 1/R

1/RT = 3/R

RT = R/3

The voltage drop across each lightbulbs will be the same for parallel connection, hence;

Power = 3V^2/(R/3)

Power = 9V^2/R

Hence the total power delivered by the battery if the lightbulbs are connected is 9V^2/R

Learn more on power here: brainly.com/question/24858512

#SPJ4

8 0

2 years ago

Helppppppp its exam

UkoKoshka [18]

Answer:

a. 240.2 C

Explanation:

7 0

3 years ago

What is the net force (including direction and magnitude) acting on the object on the above left?

Ber [7]

Answer:

Explanation:

the net force on the right left is 25 N and is directed upward

the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero

i hope this will help you

7 0

3 years ago

A bicyclist accelerates from a stop to a speed of 12m/s in 3 seconds.what is her acceleration

AVprozaik [17]

Answer:

4m/s2

Explanation:

acceleration=v-u/t...v=12m/s,u=0m/s,t=3sec

a=12-0/3

=4m/s2

8 0

3 years ago

A car travels a distance of 100 km. For the first 30 minutes it is driven at a constant speed of 80 km/hr. The motor begins to v

gregori [183]

Explanation:

First, we need to determine the distance traveled by the car in the first 30 minutes, $d_{\frac{1}{2}}$ .

Notice that the unit measurement for speed, in this case, is km/hr. Thus, a unit conversion of from minutes into hours is required before proceeding with the calculation, as shown below

$d_{\frac{1}{2}\text{h}} \ = \ \text{speed} \ \times \ \text{time taken} \\ \\ \\ d_{\frac{1}{2}\text{h}} \ = \ 80 \ \text{km h}^{-1} \ \times \ \left(\displaystyle\frac{30}{60} \ \text{h}\right) \\ \\ \\ d_{\frac{1}{2}\text{h}} \ = \ 80 \ \text{km h}^{-1} \ \times \ 0.5 \ \text{h} \\ \\ \\ d_{\frac{1}{2}\text{h}} \ = \ 40 \ \text{km}$

Now, it is known that the car traveled 40 km for the first 30 minutes. Hence, the remaining distance, $d_{\text{remain}}$ , in which the driver reduces the speed to 40km/hr is

$d_{\text{remain}} \ = \ 100 \ \text{km} \ - \ 40 \ \text{km} \\ \\ \\ d_{\text{remain}} \ = \ 60 \ \text{km}$ .

Subsequently, we would also like to know the time taken for the car to reach its destination, denoted by $t_{\text{remian}}$ .

$t_{\text{remain}} \ = \ \displaystyle\frac{\text{distance}}{\text{speed}} \\ \\ \\ t_{\text{remain}} \ = \ \displaystyle\frac{60 \ \text{km}}{40 \ \text{km hr}^{-1}} \\ \\ \\ t_{\text{remain}} \ = \ 1.5 \ \text{hours}$ .

Finally, with all the required values at hand, the average speed of the car for the entire trip is calculated as the ratio of the change in distance over the change in time.

$\text{speed} \ = \ \displaystyle\frac{\Delta d}{\Delta t} \\ \\ \\ \text{speed} \ = \ \displaystyle\frac{100 \ \text{km}}{(0.5 \ \text{hr} \ + \ 1.5 \ \text{hr})} \\ \\ \\ \text{speed} \ = \ \displaystyle\frac{100 \ \text{km}}{2 \ \text{hr}} \\ \\ \\ \text{speed} \ = \ 50 \ \text{km hr}^{-1}$

Therefore, the average speed of the car is 50 km/hr.

8 0

3 years ago