Answer:
The magnitude of change in momentum of the ball is 
and impulse is also
Explanation:
Given:
Velocity of a pitched ball 
Velocity of ball after impact 
From the formula of change in momentum,
Here mass is not given in question,
Mass of ball is 
Change in momentum is given by,
Magnitude of change in momentum is
And impulse is given by
So impulse and
Therefore, the magnitude of change in momentum of the ball is and impulse is also 
This is called an organ. Examples of organs are: your heart, brain, lungs, liver, stomach etc.
The chemical element of atomic number 20. A soft grey metal. hope this helps.
Hi, thank you for posting your question here at Brainly.
This problem could be solved using this equation:
Diffraction limit = 1.22*wavelength/diameter
diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m
Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.
Let a = the acceleration of descent., m/s².
Let u = initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u, v, and a are measured as positive upward.
Then
u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a (1)
Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600 (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²
From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s
Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.
