According to the <u>Third Kepler’s Law of Planetary motion</u> “<em>The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>
In other words, this law states a relation between the orbital period 
of a body (moon, planet, satellite) orbiting a greater body in space with the size 
of its orbit.
This Law is originally expressed as follows:
<h2>
(1)
</h2>
Where;
is the Gravitational Constant and its value is 
is the mass of Jupiter
is the semimajor axis of the orbit Io describes around Jupiter (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)
If we want to find the period, we have to express equation (1) as written below and substitute all the values:
<h2>
(2)
</h2>
Then:
<h2>
(3)
</h2>
Which is the same as:
<h2>
</h2>
Therefore, the answer is:
The orbital period of Io is 42.482 h
The right answer for the question that is being asked and shown above is that: "A.tectonic activity concentrated in certain areas." A piece of evidence did Alfred Wegener use to develop the theory of continental drift is that <span>A.tectonic activity concentrated in certain areas</span>
Answer:
Normal Conversation: i=106i0
i(dB)=60
Power saw a 3 feet: i=1011i0
i(dB)=110
Jet engine at 100 feet: i=1018i0
i(dB)=180
Explanation:
if these are the same as edge, then these are the answers! :)
Answer:
Explanation:
From the information given,
V = 4 volts
A = 2 amps
a)
In the first instance, one light on the sting goes out and the whole string of lights no longer turns on. This means that the circuit is a series circuit.
b) Total voltage = 4 x 100 = 400 V
The current passing through each bulb is the same. Thus
Total Current = 2 Amps
Recall, V = IR
R = V/I
Thus,
Resistance = 400/2
Resistance = 200 ohms
c) In this case, one light goes out on the string all other lights still turn on. This means that the circuit is a parallel circuit
d)
The voltage is the same
Total voltage = 4 volts
Total current = 2 x 100 = 200 amps
Total resistance = 4/200
Total resistance = 0.02 ohms
