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3 years ago

7

What was the name of the first steam-powered locomotive that was developed by george stephenson?

1 answer:

Natalija [7]3 years ago

4 0

It was called the Blucher, and was made in 1814.

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The parallax method of measuring star distances gives most accurate results when the gap between two observations of a star is a

EleoNora [17]

<span>b. It ensures that measurements are taken from two points
that are very far apart.

Measurements taken six months apart are the farthest apart
that an astronomer can ever get ... they're on opposite sides
of the Earth's orbit !</span>

8 0

4 years ago

Read 2 more answers

Which group was guaranteed voting rights by the Fifteenth Amendment?

castortr0y [4]

Explanation:

The 15th Amendment to the U.S. Constitution granted African American men the right to vote by declaring that the "right of citizens of the United States to vote shall not be denied or abridged by the United States or by any state on account of race, color, or previous condition of servitude." Although ratified on February 3, 1870, the promise of the 15th Amendment would not be fully realized for almost a century. Through the use of poll taxes, literacy tests and other means, Southern states were able to effectively disenfranchise African Americans. It would take the passage of the Voting Rights Act of 1965 before the majority of African Americans in the South were registered to vote.

3 0

4 years ago

Read 2 more answers

Standing waves are set up on two strings fixed at each end, as shown in the drawing. The two strings have the same tension and m

uysha [10]

The beat frequency produced by the two standing waves is 13 Hz.

<h3>The wavelength of the shorter string</h3>

The wavelength of the shorter string is calculated as follows;

$L = \frac{\lambda}{2} \\\\\lambda = 2L\\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{41.9}{225} \\\\\lambda = 0.186 \ m\\\\\lambda = 18.6 \ cm\\\\L= \frac{\lambda }{2} \\\\L = \frac{18.6 \ cm}{2} = 9.3\ cm$

<h3>The length of the longer string</h3>

$L_2 = 0.58 \ cm \ + 9.3 \ cm\\\\L_2 = 9.88 \ cm \\\\\lambda _2 = 2L_2\\\\\lambda _2 = 2(9.88 \ cm)\\\\\lambda_2 = 19.76 \ cm = 0.1976 \ m$

The frequency of the longer string is calculated as follows;

$v_1 = v_2\\\\f_2 = \frac{v_2}{\lambda_2} \\\\f_2 = \frac{41.9}{0.1976} \\\\f_2 = 212 \ Hz$

<h3>Beat frequency</h3>

The beat frequency produced by the two standing waves is calculated as follows;

$F_b = 225 \ Hz \ - \ 212 \ Hz\\\\F_b = 13 \ Hz$

Learn more about beat frequency here: brainly.com/question/3086912

8 0

3 years ago

.. A 15.0-kg fish swimming at 1.10 m>s suddenly gobbles up a 4.50-kg fish that is initially stationary. Ignore any drag effec

stira [4]

Answer:

(a) 0.846 m/s

(b) 2.097J

Explanation:

Parameters given:

Mass of big fish, M = 15 kg

Mass of small fish, m = 4.5 kg

Initial speed of big fish, U = 1.1 m/s

Initial speed of small fish, u = 0 m/s (it is stationary)

(a) We apply the principle of conservation of momentum:

Total initial momentum = Total final momentum

Since both fish have the same final speed, V, (the small fish is in the mouth of the big fish), we have:

MU + mu = (M + m)*V

(15 * 1.1) + (4.5 * 0) = ( 15 + 4.5) * V

16.5 = 19.5V

=> V = 16.5/19.5

V = 0.846 m/s

The speed of the large fish after the meal is 0.846 m/s.

(b) We need to find the change in Kinetic energy of the entire system to find the total mechanical energy dissipated.

Initial Kinetic energy:

KEini = (½ * M * U²) + (½ * m * u²)

KEini = (½ * 15 * 1.1²) + (½ * 4.5 * 0²)

KEini = 9.075 J

Final Kinetic Energy:

KEfin = (½ * M * V²) + (½ * m * V²)

KEfin = (½ * 15 * 0.846²) + (½ * 4.5 * 0.846²)

KEfin = 5.368 + 1.610 = 6.978 J

Change in kinetic energy will be:

KEfin - KEini = 9.075 - 6.978

ΔKE = 2.097 J

The energy dissipated in eating the meal is 2.097 J

5 0

3 years ago

The range of human hearing is roughly from twenty hertz to twentykilohertz. Based on these limits and a value of 305 m/s for the

AnnyKZ [126]

Answer:

1. $L_s=0.0076\ m$

2. $L_l=7.62\ m$

Explanation:

Given that

f₁= 20 Hz

f₂= 20 KHz

C= 305 m/s

For open pie organ :

$L=\dfrac{C}{2f}$

<u>Shortest length :</u><u> </u>

$L_s=\dfrac{C}{2f_2}$

$L_s=\dfrac{305}{2\times 20000}$

$L_s=0.0076\ m$

<u>Longest length : </u>

$L_l=\dfrac{C}{2f_1}$

$L_l=\dfrac{305}{2\times 20}$

$L_l=7.62\ m$

7 0

3 years ago