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3 years ago

Numerical

Physics

1 answer:

ira [324]3 years ago

5 0

Answer:

Thus, 4 kg mass must be suspended from a steel wire 2 m long and 1 mm diameter to stretch it by 1 mm.

Explanation:

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Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl

melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

$Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar$

The boundary layer thickness is equal to:

$\delta=\frac{4.91*1}{Re^{0.5} } =\frac{4.91*1}{246507^{0.5} } =0.0098$ ft

The shear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{1} )(246507)^{0.5} =0.012$

b) If the railing edge is 2 ft, the Reynold number is:

$Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar$

The boundary layer is equal to:

$\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft$

The sear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{2} )(493015.6^{0.5} )=0.0082$

c) The drag coefficient is equal to:

$C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019$

The friction drag is equal to:

$F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf$

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3 years ago

Your family decided to go to sea World in San Antonio this weekend. If it takes

Ne4ueva [31]

Answer:

63 mph

Explanation:

252/4 is 63mi

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3 years ago

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A rubber ball is dropped and bounces vertically from a horizontal concrete floor. If the ball has a speed of 3 m/s just before s

Ganezh [65]

Answer:

F=12.5N

Explanation:

Net force = rate of change of momentum

$F = m*a$

so find the change of momentum P

Pdown

$P=m*v_1=0.42kg*3m/s$

Pup

$P=m*v_1=0.42kg*6.5m/s$

dP = change in P

$dP= 0.42kg (3- -.6.5)m/s =3.99 kg m/s$

$dT = 0.32 s$

$F = \frac{dP}{dt}=\frac{3.99Kg*m/s}{0.32s} =12.468 N$

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3 years ago

Which reaction takes place in a nuclear fission reactor?

anzhelika [568]

Answer:

Last option in the list of possible answers, with U235 and n (neutron) in the left (originators) of the reaction diagram.

Explanation:

Uranium 235 (which is a fissile isotope of uranium) plus slow neutrons is what produce the chain reaction that feeds nuclear reactors.

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3 years ago

What would most likely happen if the power lines in a petroleum power plant were broken

Vaselesa [24]

<span>Customers would not get electricity. If the transmission lines [heavy power] leaving the plant broke [zap], it's just fix the transmission lines. But if the generators or main switch gear were lost, so the plant itself has no power, it can get ugly. </span>

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3 years ago

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