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Tomtit [17]
3 years ago
15

How much power is used by 4 A appliance that is plugged into a 120 V circuit for 4 minutes

Physics
1 answer:
Sever21 [200]3 years ago
8 0

Answer:

Power, P = 480 W

Explanation:

It is required to find the power used by 4 A appliance that is plugged into a 120 V circuit for 4 minutes. Power used by an appliance is given by the formula as follows :

P=VI

Plugging all the values we get :

P=120\times 4\\\\P=480\ W

So, the power used by the appliance is 480 W.

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Floating. When you have no gravity you have nothing to be pushing you down to the floor so that would be an example of no gravity pushing on you.
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3 years ago
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The quantity x to be determined from the equation X=P-Q.
Softa [21]

Answer:

the correct answer will be 6.82 %that is 7%

p(1.27)-q(0.83) =x=0.44

0.02+0.01 =0.03 (maximum uncertainty)

percentage uncertainty =0.03/0.44×100 %

=6.82%

=7%

Explanation: it was d on my end

5 0
2 years ago
A car hits a wall with a force of 80 N and
ASHA 777 [7]
Formula for acceleration: A=Force/Mass
A=F/M
A=80N/4.5kg
A=17.7 m/s^2

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5 0
3 years ago
A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0
3 years ago
The vertical motion of mass A is defined by the relation x 5 10 sin 2t 1 15 cos 2t 1 100, where x and t are expressed in millime
nikklg [1K]

Explanation:

Given that,

The vertical motion of mass A is defined by the relation as :

x=10\ sin2t+15\ cos2t+100

At t = 1 s

x=10\ sin2+15\ cos2+100

x = 115.33 mm

(a) We know that,

Velocity, v=\dfrac{dx}{dt}

v=\dfrac{d(10\ sin2t+15\ cos2t+100)}{dt}

v=20\ cos2t-30\ sin2t

At t = 1 s

v=20\ cos2-30\ sin2

v = 18.94 mm/s

We know that,

Acceleration, a=\dfrac{dv}{dt}

a=\dfrac{d(20\ cos2-30\ sin2)}{dt}

a=-40\ cos2t-60\ cos2t

At t = 1 s

v=-40\ cos2-60\ cos2

a=-99.93\ mm/s^2

(b) For maximum velocity, \dfrac{dv}{dt}=a=0

-40\ cos2t-60\ cos2t=0

t = 45 seconds

For maximum acceleration, \dfrac{da}{dt}=0

80\ sin2t+120\ cos2t=0

t = 61.8 seconds

Hence, this is the required solution.

5 0
4 years ago
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