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balandron [24]
3 years ago
9

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude

of the electric field strength between them, if the potential 7.35 cm from the zero volt plate (and 2.65 cm from the other) is 533 V
Physics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

E=6.8Kv/m

Explanation:

From the question we are told that

Distance b/w plate d=10cm=>0.1m

P_1 Potential at 7.35 V=533v

Generally the equation for electric field at a distance is mathematically given as

E=\frac{v}{d}

E=\frac{533}{7.85*10^-^2}

E=6789.808917

E=6.8*10^3

E=6.8Kv/m

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Which of the following can easily be studied objectively? history meteorology sociology theology
Vilka [71]
<h2>Answer: meteorology </h2>

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Unlike history, sociology and theology, in which there is a possibility of the existence of some data are subjective and not true or only based on opinions <u>without scientific evidence</u>.

8 0
3 years ago
How many swings would a 23 cm long pendulum make in 30 seconds?
iragen [17]

Is there any possible chance that at some point in your science
studies, sometime before you were given this question for your
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If the length is 0.23 meter, and the
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                                 = (2 pi) √(0.23/9.8)

                                 =   0.963... second  (rounded)

That's how long it takes for a simple pendulum, 23cm long,
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Now, if you can figure out how many periods of  0.963 second
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8 0
3 years ago
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Eva8 [605]

Answer: The angle between the two colours when they emerge is 0.4°

Explanation:

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Ni × sin α = Nr × sinβ

Where Ni is the refractive index for light in incident medium

α is the angle the incident makes with normal

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β is the angle the refracted makes with the normal

Making β the subject

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β = arcSin(1.490×sin30°)/1

β= 48.15°

For Blue color

The value of refractive index in polystyrene medium is 1.499,that is Ni= 1.499

α is 30° and Nr is the refractive index of air = 1

β = arcSin(1.499×sin30°)/1

β= 48.55°

The angle between the two colours is the difference in the angles of their refracted rays

48.55-48.15=0.4°

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Answer:D

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