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balandron [24]
3 years ago
9

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude

of the electric field strength between them, if the potential 7.35 cm from the zero volt plate (and 2.65 cm from the other) is 533 V
Physics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

E=6.8Kv/m

Explanation:

From the question we are told that

Distance b/w plate d=10cm=>0.1m

P_1 Potential at 7.35 V=533v

Generally the equation for electric field at a distance is mathematically given as

E=\frac{v}{d}

E=\frac{533}{7.85*10^-^2}

E=6789.808917

E=6.8*10^3

E=6.8Kv/m

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(a) calculate earth's mass given the acceleration due to gravity at the north pole is 9.830 m/s2 and the radius of the earth is
kakasveta [241]

(a) The value of the gravitational acceleration is given by:

g=\frac{GM}{r^2}

where

G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M is the Earth's mass

r=6371 km=6.371 \cdot 10^6 m is the Earth's radius at the pole

If we use the value for g given by the problem, g=9.830 m/s^2, and we rearrange the equation above, we find the value of the Earth's mass:

M=\frac{gr^2}{G}=\frac{(9.830 m/s^2)(6.371 \cdot 10^6 m)^2}{6.67 \cdot 10^{-11} m^3 kg^{-1}s^{-2}}=5.982 \cdot 10^{24} kg

(b) The value we found for the Earth's mass is 5.982 \cdot 10^{24} kg, and we see that this value is slightly larger than the accepted value of 5.979 \cdot 10^{24} kg.

5 0
3 years ago
A person throws a ball straight up into the air with a speed of 7.3m/s. How high does the ball go?
Colt1911 [192]

Answer:

2.6645m

Explanation:

applying motion equations we can find the answer,

v^{2}=u^{2}  +2as

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s =  distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

v^{2}=u^{2}  +2as\\0=7.3^{2} -2*10*s\\s=2.6645m

4 0
4 years ago
Distance between gas molecules in the case of:
alexira [117]

Answer:

-Increase in temperature: increase

-Decrease in temperature: decrease

-Increase in volume: increase

-Decrease in volume: decrease

-Increase in pressure: increase

-Decrease in pressure: decrease

Explanation:

-Increase in temperature:

● Molecules gain kinetic energy and move fast thus increasing distance

-Decrease in temperature:

● Kinetic energy of molecules decrease so they have smaller distance

-Increase in volume:

● Molecules have more space to move around so distance increase

-Decrease in volume:

● Less space, molecules collide with each other because of decreased distance thus increasing pressure

-Increase in pressure

● Molecules collide with each other and the walls of container increasing pressure so molecules move faster and it increases distance

-Decrease in pressure:

● Molecules collide with each other and walls of container less frequently so distance between molecules decrease

7 0
3 years ago
A brand new, giant 60” LCD TV uses 0.92 kWh of electrical energy in 1 hour. How many watts of power does the TV use in 1 hour?
Bad White [126]
The answer is 24.11 W
6 0
4 years ago
Read 2 more answers
A 1.2-kg mass suspended from a spring of spring constant 22 N.m-1 executes simple harmonic motion of amplitude 5 cm. Assuming th
liraira [26]

Answer:

d =3.7*10^{-3} m

Explanation:

From the question we are told that:

Mass m=1.2kg

Spring constant \mu=22Nm^{-1}

Amplitude A=5cm=0.05m

Generally the equation for displacement d is mathematically given by

 d = Asin(\omega t)

Where

 \omega=angular\ velocity

 \omega=\sqrt{k/m}

 \omega=\sqrt{22/1.2}

 \omega=4.2817rads^{-1}

Therefore  

 d = 0.05*sin(4.2817*1)  

 d =3.7*10^{-3} m

7 0
3 years ago
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