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2 years ago

The radius of a circle is 7 m. Find its area to the nearest tenth

Mathematics

1 answer:

BaLLatris [955]2 years ago

3 0

Answer:

153.9

Step-by-step explanation:

Area of a circle formula:

Pi*r*r of Pi*r^2

pi*7*7= Area of circle

pi*49

49* 3.14 is around 153.86 which is around 153.9

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9. If ground beef costs $4.98 for 3 pounds, then what is the unit rate (cost per

Drupady [299]

Answer:

1.66 pounds

Step-by-step explanation:

4.98 dollars divided by 3 pounds

4 0

2 years ago

Can someone help asap!!

Alborosie

7/9÷4/9=7/4

= 1/3/4

Hence, a=1, b=3, c=4.

hope it helps:)))

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2 years ago

In a class of 27 students, five students have 1 pet.

Digiron [165]

Answer:

yes, the student who has 8 pets.

Step-by-step explanation:

the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"

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2 years ago

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PLS HELP:( !! What is an equation of the line

pychu [463]

Answer:

$y = \frac{3}{2} x + 8$

Step-by-step explanation:

The given equation is written in the form of y=mx+c (where m is the gradient and c is the y-intercept).

Thus, gradient of given equation= -⅔

The products of the gradient of perpendicular lines is -1.

(Gradient of line)(-⅔)= -1

Gradient of line

$= - 1 \div ( - \frac{2}{3} ) \\ = \frac{3}{2}$

Hence, m= $\frac{3}{2}$ .

Subst. m= $\frac{3}{2}$ into the equation:

$y = \frac{3}{2} x + c$

To find the value of c, substitute a pair of coordinates into the equation:

When x= -4, y= 2,

$2 = \frac{3}{2} ( - 4) + c \\ 2 = - 6 + c \\ c = 2 + 6 \\ c = 8$

Thus, the equation of the line is $y = \frac{3}{2} x + 8$ .

3 0

2 years ago

Read 2 more answers

Solve for y 16y^2-25=0

Pepsi [2]

Answer:

$\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

Step-by-step explanation:

$16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}$

$METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

7 0

2 years ago

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