Hello how are you doing so the answer for this question is going to be maybe it’s going to be A
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
Answer:
x | y
10 1 = 1/2 (10) -4=5-5= 1
-2 -5 = 1/2(-2)-4=-1-4= -5
4 -2 = 1/2(4)-4=2-4= -2
-8 -8 = 1/2(-8)-4=-4-4= -8
Answer:
Unit rate is found simply by dividing.
6 pages of instruction/2 pages of practice problems = 3 pages of instruction per page of practice problems
Step-by-step explanation:
Answer:
hope this helps! :)
Step-by-step explanation:
Partition the primary number of the profit (or the two first numbers if the past advance took another digit) by the principal digit of the divisor. Compose the consequence of this division in the space of the remainder. Increase the digit of the remainder by the divisor, compose the outcome underneath the profit and deduct it
