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BigorU [14]
3 years ago
15

A large container holds 2 liters of water. 45.0 grams of NaCl is added to the container. What is the molarity of sodium chloride

in the container?
Chemistry
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

THE MOLARITY OF SODIUM CHLORIDE IN THE CONTAINER IS 0.3846 M.

Explanation:

Molarity of a solution is the number of moles of solute per dm3  of solution.

Mass concentration = Molar concentration * Molar mass

1. calculate the mass concentration;

Mass conc. = 45 g in 2 L

= 45 g in 2 dm3

In 1 dm3, the mass will be 45 / 2

= 22.5 g/dm3 of NaCl.

2. Calculate the molar mass;

(Na = 23, Cl = 35.5)

Molar mass = ( 23 + 35.5 ) g/mol

Molar mass = 58.5 g/mol

3. calculate the molarity

Molarity = mss concentration / molar mass

Molarity = 22.5 g/dm3 / 58.5 g/mol

Molarity = 0.3846 mol/dm3 of NaCl.

The molarity of sodium chloride in the container is 0.3846 mol/dm3

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vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

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Explanation

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Some growth regulators are useful to farmers and gardeners.<br> O True<br> O False
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Answer:

True

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3 years ago
An unknown compound contains 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen by mass. A mass spectrometry analysis reveals that
tiny-mole [99]

Answer:

Molecular formula is C₂₆H₃₆O₄

Explanation:

The compound is 75.69 % C, 8.80 % H and 15.51 % O. This data means, that in 100 g of compound we have 75.69 g, 15.51 g and 8.80 g of, C, O and H, respectively. We know the molar mass of the compound, so we can work to solve the moles of each element.

In 100 g of compound we have 75.69 g C, 15.51 g O and 8.80 g H

In 412 g of compound we would have:

(412 . 75.69) / 100 = 311.8 of C

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(412 . 8.80) / 100 = 36.2 g of H

Now, we can determine the moles of each, that are contained in 1 mol of compound.

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