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irakobra [83]
3 years ago
9

A current of 0.15 A is passed through an aqueous solution of K2PtCl4. How long will it take to deposit 1.00 g Pt(s) (M = 195.1)?

Chemistry
1 answer:
murzikaleks [220]3 years ago
5 0

First calculate the electric charge used to deposit 1.0 g Pt

C = (1.0 g Pt) (1 mol Pt / 195.1 g Pt) ( 2 mol e / 1 mol Pt) ( 96485 C / 1 mol e)

C = 989.08 C

C = It

Where I is the current

T is the time

T = C / i

T = 989.08 C / 0.15 A

T = 6593.88 s

T = 1.83 hrs

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Using 3 O2 molecules and 5 H2 molecules, how many water molecules can be produced? Do you have any left over?
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We have 4.98×10⁻²⁴ moles O₂ and we used 4.15×10⁻²⁴ moles.

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1 mol is contained by NA molecules

0.83×10⁻²⁴ moles are contained by (0.83×10⁻²⁴ . 6.02×10²³) = 0.5 molecules

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