<h2>Answer : Option D) Solutions of salt and water conduct electricity.
</h2><h3>Explanation :</h3>
The best description of salt is that when they are dissolved in water they dissociate into ions and become electrolytic in nature. This is observed that these solutions of salt will conduct electricity. Dissociation of ions helps the solution to conduct electricity. Usually salts dissociate into respective cations and anions of the salt compound. Most of the salts can be obtained as a product from neutralization reactions.
Answer:
The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ
Explanation:
From Arrhenius equation showing the temperature dependence of reaction rates.
where
k = rate constant
A = Frequency or pre-exponential factor
Ea = energy of activation
R = The universal gas constant
T = Kelvin absolute temperature
we have

Where
f = fraction of collision with energy higher than the activation energy
Ea = activation energy = 10.0kJ = 10000J
R = universal gas constant = 8.31 J/mol.K
T = Absolute temperature in Kelvin = 400K
In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature
Plugging in the values into the equation relating f to activation energy we get
or f =
= 20.22 moles of argon have an energy of 10.0 kJ or greater
Answer:
9.47 mL
Explanation:
The reaction that takes place is:
- 2KOH + H₂SO₄ → K₂SO₄ + 2H₂O
First we <u>calculate how many KOH moles reacted</u>, using <em>the given concentration and volume of KOH solution</em>:
- 0.061 mol/L = 0.061 mmol/mL
- 0.061 mmol/mL * 26.7 mL = 1.6287 mmol KOH
Then we <u>convert KOH moles into H₂SO₄ moles</u>, using the <em>stoichiometric coefficients</em>:
- 1.6287 mmol KOH *
= 0.8144 mmol H₂SO₄
Finally we <u>calculate the required volume of the H₂SO₄ solution</u>, using<em> the number of moles and given concentration</em>:
- 0.8144 mmol ÷ 0.086 mmol/mL = 9.47 mL
Answer:
The correct answer is KNO3
Explanation:
Pb(NO3)2 +2 KCl -> PbCl2 + KNO3
If we look at the left side of the equation we could see that there are 1 lead atom, 2 nitrate atoms ,2 potassium atoms and 2 chlorine atoms
Now when we look at the right side of the equation, we found that there are –
1 lead atom and 2 chlorine atoms (PbCl2) , thus lead and chlorine are balanced as they have the same number of atom in LHS and RHS
There is only 1 potassium and 1 nitrate atom on RHS , thus KNO3 is not balanced.
The balanced equation would be –
Pb(NO3)2 +2 KCl -> PbCl2 +2 KNO3