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mr Goodwill [35]
3 years ago
6

Which phrases accurately describe an elliptical galaxy?

Physics
2 answers:
wolverine [178]3 years ago
6 0

Answer:

may be egg shaped or may be spiral shaped has no recognizable shape has no new stars being formed has almost no gas or dust between stars.

Jlenok [28]3 years ago
3 0

Answer:a

Explanation:

May be spiral shaped

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The nitrogen fixation is the process of conversion of nitrogen gas into a usable form.

Answer: Option 3

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The nitrogen fixation is the process where the nitrogen gas present in air gets trapped and converted into ammonia or other nitrogenous compounds. This is the first step of nitrogen cycle.

The atmospheric nitrogen will get absorb in soil and gets converted to either ammonia which acts as nutrition for plants or other nitrogen related compounds which acts as fertilizers.

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Two linear polarizing filters are placed one behind the other, so that their transmission directions are parallel to one another
ale4655 [162]

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0.5I0

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Because once ligh passes though any polarizer 50% of it is gone.  The second polarizer is also oriented in the same direction so it passes through with no effect.

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4 years ago
A planet has two small satellites in circular orbits around the planet. The first satellite has a period 18.0 hours and an orbit
sasho [114]

Answer:

Time period of second satellite will be 50.904 hour

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We have given time period of first satellite T_1=18hour

Orbital radius of first satellite a_1=2\times 10^7m

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We have to find the time period of second satellite.

Time period of satellite is equal to T=2\pi \sqrt{\frac{a^3}{G(M_1+M_2)}}

From the relation we can see that T\propto a^{\frac{3}{2}}

\frac{T_1}{T_2}=\frac{a_1^\frac{3}{2}}{a_2^\frac{3}{2}}

\frac{18}{T_2}=\frac{(2\times 10^7)^\frac{3}{2}}{(4\times 10^7)^\frac{3}{2}}

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Time period of second satellite will be 50.904 hour

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