Answer:
Percent yield of 4-bromo Acetanilide from the reaction is 0.586
Explanation:
The equation of reaction is
Acetanilide + Bromine ----> 4-bromo Acetanilide.
That is,
C₆H₅NHCOCH₃ + Br₂ -----> (4-Br)C₆H₄NHCOCH₃
1 mole of Acetanilide gives 1 mole of 4-bromo Acetanilide
We need to to acquire the number of reacted Acetanilide. (the entire Acetanilide reacts, since Bromine is in excess)
Number of moles = mass of Acetanilide/Molar mass of acetanilide
Mass of reacted Acetanilide = 125mg = 0.125g, molar mass of Acetanilide = 135.17 g/mol
Number of moles of reacted Acetanilide = 0.125/135.17 = 0.000925 moles
From the stoichiometric balance of the reaction,
1 mole of Acetanilide gives 1 mole of 4-bromo Acetanilide
0.000925 mole of Acetanilide will give 0.000925 mole of 4-bromo Acetanilide
Theoretical mass of 4-Bromo Acetanilide = Stoichiometric number of moles × Molar mass = 0.000925 × 214.06 = 0.198g = 198mg.
Percentage yield = (Actual yield/Theoretical yield) = 116/198 = 0.586.
Hope this helps!!
