Question

For the reaction bro3- + 5br- + 6h+ → 3br2 + 3h2o at a particular time, -δ [bro3-]/δt = 1.5 × 10-2 m/s. what is -δ [br-]/δt at the same instant?

Answer 1

Answer:

7.5 M/s

Explanation:

The equation of Reaction is given as;

BrO^3- + 5Br^- + 6H^+ --------------> 3Br2 + 3H2O. ----------------------------(1)

Rate of Reaction is the speed in which reaction take place for the transformation of reactants to products.

For the reaction (1) above;

===> - (∆[BrO^3-]/ ∆t) = -(∆Br^-])/∆t = -∆[H^+] /∆t = ∆[Br2]/∆t.

Notice from above that there is negative signs at the Change in the reacti species. This is so, because the Reactants is been used up in the reaction to produce the products

NB : I did not raise the number of the moles to the power of each species to avoid clumsiness.

We are given that; - (∆[BrO^3-]/ ∆t) = 1.5 × 10^-2 m/s; -(∆Br^-])/∆t = x m/s.

1 mole of BrO3^- = 5 mole of Br^-

So, 5 × 1.5 ×10^-2 .

= 7.5 × 10 ^-2 M/s

Answer 2

The $  -(Br)   at  that  instant   is  calculated  as  follows
BrO3  + 5Br  --->  3Br2  +  3 H2o

by   use    of  reacting  ratio  BrO3   to  Br2  which   is   1:3

therefore   $  of  Br  =  3  x   (1.5 x10^-2)= 4.5 x10^-2