Accuracy is when the observations are closest to the actual value, while precise isn't necessarily close to the actual value, but different observations are close to each other.
E.G
Accuracy: Getting the bullseye each time.
Precise: Darts landing on the same part of the board everytime.
Accuracy is the most important though, since the actual value is more valuable than values that just so happen to be close together.
Complete Question:
A chemist adds 55.0 mL of a 1.1M barium acetate (Ba(C2H3O2)2) solution to a reaction flask. Calculate the mass in grams of barium acetate the chemist has added to the flask. Round your answer to 2 significant digits.
Answer:
15 g
Explanation:
The concentration of the barium acetate is given in mol/L (M), thus, the number of moles (n) of it is the concentrantion multiplied by the volume (55.0 mL = 0.055 L):
n = 1.1 * 0.055
n = 0.0605 mol
The molar mass of the substance can be calculated by the sum of the molar mass of each element, which can be found at the periodic table. Thus:
Ba = 137.33 g/mol
C = 12.00 g/mol
H = 1.00 g/mol
O = 16.00 g/mol
Ba(C2H3O2)2 = 137.33 + 4*12 + 6*1 + 4*16 = 255.33 g/mol
The molar mass is the mass divided by the number of moles, thus the mass (m) is the molar mass multiplied by the number of moles.
m = 255.33 * 0.0605
m = 15.45 g
Rounded by 2 significant digits, m = 15 g.
There are 3 sig figs mark me brainliest please
Answer:
Filled below
Explanation:
#v.e means number of valence electrons.
Also, the column total v.e is gotten by adding the v.e of the metal to the v.e of the non metal based on the chemical formula of both of the 2 elements combined.
K: Cl: 5; KCl; 1 + 5 = 6
Be: S: 6; BeS; 2 + 6 = 8
Na: F: 7; NaF; 1 + 7 = 8
Mg: Se: MgSe; 2 + 6 = 8
Al; N; AlN; 1 + 5 = 6
Be; F; BeF2; 2 + 2(7) = 16
Mg; N; Mg3N2; 3(2) + 2(7) = 20
Answer:
200 grams of sodium hydroxide produce 595 grams of sodium sulfate if we have an excess of sulphuric acid
Explanation:
2 NaOH + H2SO4 → 2 H20 + Na S04
From the above chemical equation we can state that
2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate.
Now if we start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid then the amount in grams of sodium sulfate will be formed
2 moles of sodium hydroxide produce 1 mole of sodium sulfate.
In term of mass, we can say that
40 grams of sodium hydroxide produce 119grams of sodium sulfate
1 grams of sodium hydroxide produce (119/40) grams of sodium sulfate
then 200 grams of sodium hydroxide produce ((119*200)/40) grams of sodium sulfate
or 200 grams of sodium hydroxide produce 595 grams of sodium sulfate