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Minchanka [31]
3 years ago
6

A steam power plant produces 50MW of net work while burning fuel to produce 150MW of heat energy at the high temperature. Determ

ine the cycle thermal efficiency and the heat rejected by the cycle to the surroundings.
Physics
1 answer:
Mazyrski [523]3 years ago
3 0

Nth =\frac{W net, out}{Qh}

50MW is our net output.

Then, we plug it in.

= \frac{50MW}{150MW} = 0.333 or 33.33%

W net, out = Qh - Ql

Ql = Qh - W net,out

Plug the values in.

Then, it becomes:

= 150MW - 50 MW

= 100MW

Thus, the cycle thermal efficiency is 33.33% and the heat rejected is 100MW.

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Crank

Answer:

Hmax=15.06 meters

Explanation:The question ask for the maximum value of the function f(t) which can be find by find the maxima of the function

The maxima of the function occurs when the slope is zero. i.e.

\frac{df}{dt} =0\\\frac{df}{dt} =\frac{d}{dt} (-4.9t^2+16t+2)\\\frac{df}{dt} =-4.9*2t+16\\-9.8t+16=0\\t=16/9.8\\t=1.63 secs

Hence the maxima occurs at t=1.63 seconds

The maximum value of f is

f(1.63)=-4.9(1.63^2)+16(1.63)+2\\f(1.63)=15.06\\

hence maximum height is found to be

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8 0
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