Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
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What is Escape Velocity ?</h3>
This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
- Mass (m) of the rocket 0.25 Kg
- Initial velocity u = 15 m/s
- Final Velocity v = 40 m/s
- Gravitational field intensity g = 9.8N/kg
The force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
Learn more about Escape Velocity here: brainly.com/question/13726115
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Answer:
the mass of 1000 kg
Explanation:
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Answer: Voltage
Voltage
is the measure of force or potential energy that required moving a unit charge
from one location to another through a conductor. This potential energy is
stored in the form of an electric charge imbalance and capable of provoking
electrons to flow in material through which charges can easily flow.
Answer:
no
Explanation:
it is not healthy because sodium is not good to our body
