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3 years ago

A gun has a muzzle speed of 150 m/s. Find two angles of elevation that can be used to hit a target 800m away.

Physics

1 answer:

lorasvet [3.4K]3 years ago

4 0

Answer:

Explanation:

u = 150 m/s

R = 800 m

The formula for the horizontal range is

$R=\frac{u^{2}Sin2\theta }{g}$

where, θ is angle of projection.

$800=\frac{150^{2}Sin2\theta }{9.8}$

Sin2θ = 0.348

2θ = 20.4°

θ = 10.2°

The range is same for the complementary angles.

So, the other angle is 90 - 10.2 = 79.8°

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Answer:

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I hope it helps you!

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