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KATRIN_1 [288]
3 years ago
6

A gun has a muzzle speed of 150 m/s. Find two angles of elevation that can be used to hit a target 800m away.

Physics
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

Explanation:

u =  150 m/s

R = 800 m

The formula for the horizontal range is

R=\frac{u^{2}Sin2\theta }{g}

where, θ is angle of projection.

800=\frac{150^{2}Sin2\theta }{9.8}

Sin2θ = 0.348

2θ = 20.4°

θ = 10.2°

The range is same for the complementary angles.

So, the other angle is 90 - 10.2 = 79.8°

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Dominik [7]

Answer:

14.8m

Explanation:

Given parameters:

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Unknown:

Maximum height  = ?

Solution:

At the maximum height, the final speed will be 0m/s;

 We use of the kinematics equation to solve this problem.

     V²   = U²   - 2gH

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g is the acceleration due to gravity

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          0 = 289  - (9.6h)

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Kobotan [32]

Answer: looks good

Explanation:

3 0
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4 0
3 years ago
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Masteriza [31]

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